Given a 4-bit signed input P=P3P2P1P0 and a control input Z, use a 4-bit adder and any logic gates to design a digital circuit that does the following: • Outputs P + 3, if the input Z = 0 • Outputs P - 3, if the input Z = 1
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- Write the three outputs of X, Y and Z in terms of the four inputs A, B, C and D for the follow logic gates configuration ---This is my answer: I am unsure if it is right. X = A + (A’B’ * (B’+C’) = A + (A’+B’)*(B’*C’) Y = ((A’+B’)*(B’*C’))*((B’*C’)+CD)Z = (B+C)*(C’+D’)*D’let consider 5 different outputs in combinational circuit/ Digital Logic Design For example x=1 y= 0 a =1 b= 1 c=0 Design a single output schema which take the 5 different outputs into a single 5 bit output Y[4:0] Y output will be for example 5 bits 10110Given a 4-bit signed integer, design a circuit that outputs its absolute value. You can assume that the input will always have a valid output. (a) Draw a logic diagram of this circuit. You may use 4-bit half adder(s), 2x1 4-bit multiplexer(s), and any logic gate(s) in your design. (b) With the following Verilog code, implement your design above in Verilog. module half_adder (input [3:0] a, input [3:0] b, output [3:0] s); assign s = a + b; endmodule module mux(input [3:0] D0, input [3:0] D1, input S, output reg [3:0] O); always @(*) begin if (S == 0) O = D0; else if (S == 1) O = D1; else O = 4’bx; end endmodule
- A combinational circuit with four inputs (A,B,C,D) and one output (Z) is designed as follows using an 8:1 multiplexer. Inputs A,B,C are connected to the select lines ?S2, S1, S0 respectively. Multiplexer has the following values connected to the data inputs: I0,I6 =1; I1,I3 =D; I2,I5 =0; I4,I7 =D’ Write the simplest logic expression of the circuit realized above Z= f(A, B, C, D)the following combinational circuit takes two 4-bit numbers( A , B) and takes a single bit control input (incA / ̅̅̅̅̅). And produce 4-bit result If (incA / ̅̅̅̅̅) = 1 then the circuit would increment A by 1 If (incA / ̅̅̅̅̅) = 0 then the circuit would add A and B implement this circuit using only combinational components (no gates)Design a combinational logic circuit that takes a 3–bit input and has one output P. The P output should be active high only when the inputs corresponds to a prime number Note: the prime numbers: Prime numbers are 2, 3, 5, 7… Select one: a. P= AC+B b. P= A'C+A'B c. P= AC+A'B d. P= AC+A'B'
- Design the simplest circuit that has three inputs, a, b, and c, which returns an output value of 1 whenever g and b are complements of each other or b and c are complements of each other, otherwise the output is 0. Realize the circuit using 4input , 3output PALDesign a combinational circuit with three inputs x, y, z, and three outputs a, b, and c. When the binary input is 0, 1,2, or 3 , the binary output is 1 greater than the input. When the binary input is 4, 5, 6, or 7, the binary output is one less than the input.The digital logic family which has the lowest propagation delay time is (A) ECL(B) TTL(C) CMOS(D) PMOS
- Design a combinational circuit with three inputs x, y, and z and three outputs A, B, and C. When the binary input is 0, 1, 2, or 3, the binary output is one greater than the input. When the binary input is 4, 5, 6, or 7, the binary output is two less than the input.Design a circuit that compares two 3-bit numbers A and B to check if they are equal and less than. The circuit has two outputs X and Y, So that X=1 if A==B and X=0 if A!=B and Y=1 if A<B and Y=0 if A>BDesign a combinational circuit with three inputs, x , y , and z , and three outputs, A, B, and C . When the binary input is 0, 1, 2, or 3, the binary output is two greater than the input. When the binary input is 4, 5, 6, or 7, the binary output is two less than the input.