Given a string in which the same.character occurs in many consecutive character elements, Your task is to find the char acters'that have even frequency and are consecutive 'DIsplay the sum of every frequency count (For even frequency only). Example1: Input aaabbaccccdg Output: Oout String hà Explanation: Input string aut times, againA Here, the frenteucy of b frequency cqunt is 2,4 And 2 respectwely Hence the output# OrREn/a3 mes, b' 2 and dis even and the +23D8

Given a string in which the same.character occurs in many consecutive character elements, Your task is to find the char acters'that have even frequency and are consecutive 'DIsplay the sum of every frequency count (For even frequency only). Example1: Input aaabbaccccdg Output: Oout String hà Explanation: Input string aut times, againA Here, the frenteucy of b frequency cqunt is 2,4 And 2 respectwely Hence the output# OrREn/a3 mes, b' 2 and dis even and the +23D8

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter7: User-defined Simple Data Types, Namespaces, And The String Type

Section: Chapter Questions

Problem 8PE: Write a program that reads in a line consisting of a students name, Social Security number, user ID,...

See similar textbooks

Similar questions

C++ only. Do not copy. Correct code will upvoted else downvote. play out the accompanying activity until the string becomes vacant: pick some successive substring of equivalent characters, eradicate it from the string and paste the leftover two sections together (any of them can be vacant) in a similar request. For instance, in the event that you eradicate the substring 111 from the string 111110, you will get the string 110. At the point when you erase a substring of length l, you get a⋅l+b focuses. Your errand is to compute the greatest number of focuses that you can score altogether, on the off chance that you need to make the given string unfilled. Input The primary line contains a solitary integer t (1≤t≤2000) — the number of testcases. The primary line of each testcase contains three integers n, an and b (1≤n≤100;−100≤a,b≤100) — the length of the string s and the boundaries an and b. The subsequent line contains the string s. The string s comprises just of the…
c language, how to modify this code to add word count before and after the word removal. Thanks! the output picture is what the output should look like except the output does not work for word removal but the code below can only do word removal but not the word count. please help. #include <stdio.h>#include <string.h> void removeSubstr(char *string, char *sub){ char *match; int len = strlen(sub); while ((match = strstr(string, sub))){ *match = '\0'; strcat(string, match+len); }} int main(){ char string[100], word[100]; printf ("Enter the string: "); //user input a sentence fgets(string,100,stdin); printf ("Enter the word to be removed: "); //inputs the words to be removed gets(word); printf("The words after removing: "); removeSubstr(string, word); puts(string); return 0;}
please provide me flow chart for the foolowing code please do not copy and paste from another place as answer will dislike #include<iostream>#include<fstream>#include<string.h>#include<iomanip> using namespace std; struct marks { string id; double quiz[2], ass[2], labTest[2]; double test, proj, final, total; char grade;}; struct marks s_marks[50]; void studentGrade(int i) { s_marks[i].total = ((s_marks[i].quiz[0] + s_marks[i].quiz[1]) * 0.05) + ((s_marks[i].ass[0] + s_marks[i].ass[1]) * 0.15) + ((s_marks[i].labTest[0] + s_marks[i].labTest[1]) * .20) + (s_marks[i].test * 0.15) + (s_marks[i].proj * 0.15) + (s_marks[i].final * 0.30); if (s_marks[i].total >= 90 && s_marks[i].total <= 100) s_marks[i].grade = 'A'; else if (s_marks[i].total >= 80 && s_marks[i].total <= 90) s_marks[i].grade = 'B'; else if (s_marks[i].total >= 60 && s_marks[i].total <= 80) s_marks[i].grade = 'C'; else if…
// Task 2 // For this function, you must build a string that when printed,// will output the entire binary representation of the integer x,// no matter how many bits an integer is. You may NOT use// division (/) or mod (%) anywhere in your code, and should// instead rely on bitwise operations to read the underlying binary// representation of x.stringbuilder get_bin_1(int x) { stringbuilder sb = new_sb(); sb_append(sb, '$'); return sb;}
Teacher ask different version of this code please provide that '''Problem A DNA: CG PairsPurpose:This function will take as an argument a string containing a dna strand Parameter(s):dnaReturn Value: fraction of dinucleotides ''' def cg_pairs(dna): dna_simple = 'AGCTTTCATTCTGAC' dna= dna.lower() for i in range (0,len(dna)): if(dna[i]=='a'or dna[i]=='c'or dna[i]=='g' or dna[i]=='t' ): continue else: print("Error in DNA strand ") return 0.0 count = 0 for i in range(0,len(dna)-1): var = dna[i:i + 2] if(var=="cg"): count+=1 else: continue return (float(count/(len(dna)-1)
The program should print out a 10x10 multiplication table, using nested for() loops. It should ALSO print column headers (1 through 10) and row numbers, as shown. All numbers should be equally spaced using cout << setw(5) << variableName; so that the columns align, though the example below may not look that way in your browser. You must have #include <iomanip> at the top of your program to use the setw() function of the cout object, which sets the width of field for printing the variable's value.Expected output: * 1 2 3 4 5 6 7 8 9 10 1 1 2 3 4 5 6 7 8 9 10 2 2 4 6 8 10 12 14 16 18 20 3 3 6 9 12 15 18 21 24 27 30 4 4 8 12 16 20 24 28 32 36 40 5 5 10 15 20 25 30 35 40 45 50 6 6 12 18 24 30 36 42 48 54 60 7 7 14 21 28 35 42 49 56 63 70 8 8 16 24 32 40 48 56 64 72 80 9 9 18 27 36 45 54 63 72 81 90 10 10 20 30 40 50 60 70 80 90 100 Note that you will need an extra for () loop at the beginning to print the column headers, after you print the asterisk. And in each row…
#include <iostream> #include <ctime> #include <cmath> const int MAX = 1000; const char CLASS[] = {'A','B','C'}; struct Points{ int x,y; char c; double dist(Points q){ return sqrt(pow(x-q.x,2)+pow(y-q.y,2)); } }; int main(){ return 0; } int main(){ srand(time(0)); }
Repost Please help me explain the whole program step by step such as explain all the functions, the element, the operation, all the struct functions and so on. The coding: #include<iostream>#include<iomanip>#include<ctype.h>#include<string.h>using namespace std; struct nodeWords{ char words[100]; struct nodeWords* next;};struct undoWords{ char unwords[100]; struct undoWords* next;};undoWords* untop;undoWords* newundoNode; nodeWords* top; //these pointers are used to hold the linked list.nodeWords* current; //use for traversalnodeWords* newNode; //use to create new node for new recordnodeWords* pop; void Push() //push an element into the stack{ char answer; do { newNode = new nodeWords; cout << "\nWrite what's in your mind.." << endl; cout << "Your words > "; cin >> ws; cin.getline(newNode->words, 100); newNode->next = top; top = newNode; cout…
The loop below is intended to collect all characters that occur more than once in a given string. When you try it out with a string such as “Mississippi”, you will note that that letters that occur three or more times are collected more than once. Modify the loop so that each repeated letter is collected exactly once. For example, when s is “Mississippi”, result should be “si” and not “sissii” Only allowed to edit code in the /* Your code goes here */ portion. Thanks for the help!
I need to convert this cod to switch and case statment and put Properly commented for cods . it must run on Devc++ . #include <iostream> using namespace std; int main() {int ch;char size;string item;cout<<"Welcome to Freddy’s Pizza\nPizza Menu:\n1- Vegetarian Pizza\n2- Chicken Dynamite Pizza\n3- Meat Lovers Pizza";cout<<"\nWhich Pizza would you like to try?(Chicken/Meat/Vegetarian) ";cin>>item;cout<<"\nWhat size of pizza would you like (L, M,S)? ";cin>>size;cout<<"\nPizza Order:";cout<<"\nPizza Name:"<<item<<" Pizza";if(item=="Meat"){cout<<"\nPreparation Time: 20 Minutes";cout<<"\nCalories: 250";if(size=='L'){cout<<"\nPizza Price: 8 OMR";}else if(size=='M'){cout<<"\nPizza Price: 6 OMR";}else if(size=='S'){cout<<"\nPizza Price: 4 OMR";}cout<<"\nToppings:";cout<<"\nMinced Meat, Cheese, BBQ Sauce, Fresh Tomatos";}else if(item=="Chicken"){cout<<"\nPreparation Time: 20…
Write a program that reads in a line consisting of a students name, Social Security number, user ID, and password. The program outputs the string in which all the digits of the Social Security number and all the characters in the password are replaced by x. (The Social Security number is in the form 000-00-0000, and the user ID and the password do not contain any spaces.) Your program should not use the operator [] to access a string element. Use the appropriate functions described in Table 7-1.
Modify LiveExample 12.12 EvaluateExpression.cpp to add operators ^ for exponent and % for modulus. For example, 3 ^ 2 is 9 and 3 % 2 is 1. The ^ operator has the highest precedence and the % operator has the same precedence as the * and / operators. For simplicity, assume the expression has at most one ^ operator. Sample Run: Enter an expression: (5 * 2 ^ 3 + 2 * 3 % 2) * 4 (5 * 2 ^ 3 + 2 * 3 % 2) * 4 = 160 Code posted below, c++ please! #include <vector>#include <iostream>#include <cmath>using namespace std; #ifndef STACK_H#define STACK_H template<typename T>class Stack{public: Stack(); bool empty() const; T peek() const; void push(T value); T pop(); int getSize() const; private: vector<T> elements;}; template<typename T>Stack<T>::Stack(){} template<typename T>bool Stack<T>::empty() const{ return elements.size() == 0;} template<typename T>T Stack<T>::peek() const{ return…