You are given two strings s and t. String t is generated by randomly shuffling strings and then adding one more letter at a random position. Return the letter that was added to t. Examples findThe Difference("", "e") find The Difference ("abcd", "abcde") find The Difference ("rt", "rst") → "5" find The Difference ("gjklmn", "ghjklmn"") → "h" findTheDifference ("ae", "aea") - "a"
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- Write a program that will find the longest common substring from a series of two to many words given to you by the user. For example, your program will ask the user how many words he/she wants to compare, with two being the minimum input. The longest common substring of the strings “QWERTY”, “TEWERU”, “YWERQT” is WER. Your algorithm should work for any number of inputs (words), if there is no match of common substrings, indicate to the user with a message. A common algorithm to follow when making this program is first to prompt the user for how many words he/she wants to compare (check for valid input of a number 2 to ‘n’) and then prompt the user for the strings (words) and following this return the common substring if one is present.Correct answer will be upvoted else Multiple Downvoted. Don't submit random answer. Computer science. A string b is an aftereffect of a string an if b can be gotten from a by cancellation of a few (conceivably, zero or all) characters. For instance, "xy" is an aftereffect of "xzyw" and "xy", yet not You are given a string a. Your errand is to reorder the characters of a so that "trygub" isn't an aftereffect of the subsequent string All in all, you should find a string b which is a stage of images of the string an and "trygub" isn't an aftereffect of b We have a genuinely superb confirmation that any string can be sorted out not to contain "trygub" as an aftereffect, however this issue explanation is too short to even think about containing it Inpu The primary line contains a solitary integer t (1≤t≤100) — the number of experiments The primary line of each experiment contains a solitary integer n (1≤n≤200) — the length of a The following line contains the string an of…Given a string S, find the longest palindromic substring in S. Substring of string S: S[ i . . . . j ] where 0 ≤ i ≤ j < len(S). Palindrome string: A string which reads the same backwards. More formally, S is palindrome if reverse(S) = S. Incase of conflict, return the substring which occurs first ( with the least starting index). Example 1: Input: S = "aaaabbaa" Output: aabbaa Explanation: The longest Palindromic substring is "aabbaa".
- A finite sequence of symbols from a given alphabet will be called a string over the alphabet. A string that consists of a sequence a1, a2, a3, a4, … … … … , an of symbols will be denoted by the juxtaposition a1 a2 a3 a4 … … … … an. Given the strings: u = a2bab2and v = bab2, Evaluate the following operations for strings: (i) ԑu(ii) u + v(iii) u(u| v)(iv) v | (v | u)The reverse of a string x denoted by rev(x) and is defined by the following recursiverule: •rev(ε) = ε•rev(xa) = a.rev(x) Prove that if A is a regular set then so is the following set:rev(A) = {rev(x) : x ∈A}Given a string S, determine whether it can be split into two non-empty palindrome strings. If yes, then output two palindrome strings A and B where the concatenation of A and B is S, i.e. S = A + B.If the answer is no, output NO
- I got an error message for the answer Bartleby gave me last night as follows Input Answer alphabet = "abcdefghijklmnopqrstuvwxyz"test_dups = ["zzz","dog","bookkeeper","subdermatoglyphic","subdermatoglyphics"]def histogram(s):d=dict()for c in s:if c not in d:d[c]=1 else:d[c]+=1return d;def has_duplicate(string):# return false if each letter in s is not distincth=histogram(string)for k,v in h.items():if v>1:return truereturn falsefor string in test_dups:if has_duplicate(string):printf(string,"has duplicates")else:print(string,"has no duplicates")def main():test_dups_loop()if_name=='_main_'main() THE ERROR MESSAGE said ***TRUE NEEDS TO BE DEFINED. this is all I need from the answer code I received.Draw a DFA over the alphabet {a,b,c}that only accepts strings with no c's and an even number of a's, or an odd number of c's and an odd number of b's. For example, it should accept aa, aba, abbabaa, cbacabcb, cbcca, and abc but not aca, bacc, or aaa.Write regular expressions for the following languages. By “word”, we mean an alphabetic string separated from other words by whitespace, any relevant punctuation, line breaks, and so forth. (a) The set of all alphabetic strings;(b) The set of all lower case alphabetic strings ending with a letter b;(c) The set of all strings with two consecutive repeated words (e.g., “Humbert Humbert” and “the the” but not “the bug” or “the big bug”);(d) All strings that start at the beginning of the line with an integer and that end at the end of the line with a word;(e) All strings that have both the word grotto and the word raven in them (but not, e.g., words like grottos that merely contain the word grotto);
- Implement a method String[] dedup(String[] a) that returns the objects ina[] in sorted order, with duplicates removed.given the strings s1 and s2, not necessarily of the same lenght, create a new string consisting of alternating characters of s1 and s2 (that is, the first character of s1 followed by the first character of s2, followed by the second characters of s1, followed by the second character of s2, and so on. Once the end of either string is reached, the reminder of the longer string is added to the end of the new string. For example, if s1 contained "abc" and s2 contained"uvqxyz", then the new string should contain "aubvcwxyz". Assign the new string to the variable s3. using python and loopsPlease help me fill in the blanks The reverse of a string x, denoted rev(x), is the string obtained by writing x backwards. For example, if x = abbaaab then rev(x) = baaabba. If A is a subset of Σ*, the reverse of A, denoted rev(A), is the subset of Σ* consisting of all reverses of strings in A: rev(A)={rev(x) | x∈A} For example, rev({a,ab,aab}) = {a,ba,baa}. Suppose you are given a deterministic finite automaton M accepting a set A. Show how to construct a DFA N accepting rev(A). (Kozen would suggest putting pebbles on the final states of M and moving them backwards along transition edges.) Describe N formally (i.e. in terms of Q, δ, etc.) including the definition of acceptance. Hint: the subset construction will be helpful here. You can start with M = (Q, Σ, δ, s, F) and define the components of N in terms of the components of M. 1. DFA N = (Q_N, Σ, δ_N, s_N, F_N) where Q_N = ___ 2. DFA N = (Q_N, Σ, δ_N, s_N, F_N) where δ_N = ___ 3. DFA N = (Q_N, Σ, δ_N, s_N, F_N)…