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Given a vector field F = axxy-a, 2x, find its circulation around the path OABO shown in Fig. 2-22. SOLUTION Let us split the circulation integral into three parts. F.de OABO Along = B L˚F. · So F·de + S" F+de+ S° F path OA: F.de = 0. B F.de. y = 0, F-a,2x, dl = a dx, F.dl=0.

Given a vector field F = axxy-a, 2x, find its circulation around the path OABO shown in Fig. 2-22. SOLUTION Let us split the circulation integral into three parts. F.de OABO Along = B L˚F. · So F·de + S" F+de+ S° F path OA: F.de = 0. B F.de. y = 0, F-a,2x, dl = a dx, F.dl=0.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Given a vector field F = axxy - a, 2x, find its circulation around the path OABO shown in Fig. 2-22. SOLUTION Let us split the circulation integral into three parts. SOABO OABO F.de = 0 F.de + S" B F⋅de + °F-d F.de. B OA: OA: y = 0, Fa,2x, dl = a dx, F.dl=0. So F.de = 0. Along path path FIGURE 2-22 Path for line integral (Examples 2-14 and 2-16). y4 B r=3 X A
Transcribed Image Text:Given a vector field F = axxy - a, 2x, find its circulation around the path OABO shown in Fig. 2-22. SOLUTION Let us split the circulation integral into three parts. SOABO OABO F.de = 0 F.de + S" B F⋅de + °F-d F.de. B OA: OA: y = 0, Fa,2x, dl = a dx, F.dl=0. So F.de = 0. Along path path FIGURE 2-22 Path for line integral (Examples 2-14 and 2-16). y4 B r=3 X A
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