For the second picture Can you fix the loop for the algorithm in python class Solution:def majorityElement (self, nums: List[int]) -> int:2if len(nums) % 2 == 1:count = nums.count(nums [0])if count > len(nums) // 2:return nums[0]else:356.78nums.pop(0)temp = []for i in range(0, len(nums), 2):if nums[i] == nums[i + 1]:1011 -12temp.append(nums [i])x = self.majorityElement(temp)if nums.count(x) > len(nums) // 2:131415return x16else:17return False ull T-Mobile11:21 PM22%E LeetCode* Pick OneGiven an array nums of size n, return the majorityelement.The majority element is the element that appearsmore than [n / 2] times. You may assume thatthe majority element always exists in the array.Example 1:Input: nums =[3,2,3]Output: 3Example 2:Input: nums =Output: 2[2,2,1,1,1,2,2]AAleetcode.com

PROGRAM INTRODUCTION: Start the definition of the function to find the majority element from the…

Given an array nums of size n, return the majority element. The majority element is the element that appears more than [n / 2] times. You may assume that the majority element always exists in the array. Example 1: Input: nums = [3,2,3] Output: 3 Example 2: Input: nums = Output: 2 [2,2,1,1,1,2,2] %3D

Given an array nums of size n, return the majority element. The majority element is the element that appears more than [n / 2] times. You may assume that the majority element always exists in the array. Example 1: Input: nums = [3,2,3] Output: 3 Example 2: Input: nums = Output: 2 [2,2,1,1,1,2,2] %3D

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter12: Points, Classes, Virtual Functions And Abstract Classes

Section: Chapter Questions

Problem 29SA

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ALGO1(A)// A is an integer array, an index that starts at 11): for i=1 to n-1 do2): minIndex = findSmallest(A,i)3): exchange A[i] with A[minIndex] The sub-routine find the smallest(A, i) in Line 2, and returns the index of the smallest element in thesub-array A[i:n]Suppose the array below is provided as input to ALGO1 2 5 6 7 3 8 1 4 Fill in the Blanks At the end of the first iteration of the for loop (i.e. with i=1)1) a) the element at index 1 is : b) the element at index 4 is :   c) the element at index 7 is :
Java Quick Sort but make it read the data 10, 7, 8, 9, 1, 5 from a file not an array // Java implementation of QuickSort import java.io.*;    class GFG {        // A utility function to swap two elements     static void swap(int[] arr, int i, int j)     {         int temp = arr[i];         arr[i] = arr[j];         arr[j] = temp;     }        /* This function takes last element as pivot, places        the pivot element at its correct position in sorted        array, and places all smaller (smaller than pivot)        to left of pivot and all greater elements to right        of pivot */     static int partition(int[] arr, int low, int high)     {            // pivot         int pivot = arr[high];            // Index of smaller element and         // indicates the right position         // of pivot found so far         int i = (low - 1);            for (int j = low; j <= high - 1; j++) {                // If current element is smaller             // than the pivot             if…
// function to generate all subsequences of given arrayfunction generate_subseq(arr):    // length of arr   n = len(arr)    // total subsequences for array of length n   m = 2**n    // to store all subsequences   seqs = []    // running a loop for m times   for i in range(1, m):        // creating an array of zeros of length n       a = [0]*n        num = i       // to use as an index for 'a'       j = n-1        // run this loop till num > 0       while num > 0:            if num is odd:               a[j] = 1            // divide num by 2           num = num/2            // subtract 1 from 'j'           j -= 1        // to store current subsequence       seq = []        // iterating for n times       for i in range(n):            // add ith index value to 'seq'           if a[i] == 1:               seq.append(arr[i])        // add 'seq' to 'seqs'       seqs.append(seq)    // return seqs   return seqs // given listsS1 = ['B','C','D','A','A','C','D']S2 = ['A','C','D','B','A','C']…
6. Read in two integers n and m (n, m < 50). Read n integers in an array A. Read m integers in anarray B. Then do the following (write separate programs for each, only the reading part iscommon).a) Find if there are any two elements x, y in A and an element z in B, such that x + y = z.b) Copy in another array C all elements that are in both A and B (intersection).c) Copy in another array C all elements that are in either A and B (union).d) Copy in another array C all elements that are in A but not in B (difference).Do In c Program
// lab8ExB.cpp #include <iostream> using namespace std; void insertion_sort(int *int_array, int n); /* REQUIRES * n > 0. * Array elements int_array[0] ... int_array[n - 1] exist. * PROMISES * Element values are rearranged in non-decreasing order. */ void insertion_sort(const char** str_array, int n); /* REQUIRES * n > 0. * Array elements str_array[0] ... str_array[n - 1] exist. * PROMISES * pointers in str_array are rearranged so that strings: * str_array[0] points to a string with the smallest string (lexicographicall) , * str_array[1] points to the second smallest string, ..., str_array[n-2] * points to the second largest, and str_array[n-1] points to the largest string */ int main(void) { const char* s[] = { "AB", "XY", "EZ"}; const char** z = s; z += 1; cout << "The value of **z is: " << **z << endl; cout << "The value of *z is: " << *z << endl; cout << "The value of…
3. Implement a function called findLargestIndex which returns the index of the rowwith the largest sum.ex. int array[3][6] = {{3, 6, 8, 2, 4, 1}, // sum = 24{2, 4, 5, 1, 3, 4}, // sum = 19{1, 0, 9, 0, 1, 0}}; // sum = 11If the findLargestIndex function was called using this array, it would return 0, asit is returning the index of the row, not the sum.Note that the number of columns is required when passing a 2d array to a function.Assume that 2D arrays passed to this function will have 6 columns.Title line: int findLargestIndex(int array[][6], int rows, int columns);
Select true or false for the statements below. Explain your answers if you like to receive partial credit Select true or false for the statements below. Explain your answers if you like to receive partial credit Which of the following is true about searching elements in an unordered array? With the data is unsorted, search is O(n) because if the element you are looking for is not there, you have to check every element in the array If you start at the end of the array and traverse to index 0, search improves to O(log n) because you only have to look at half of the array If you get lucky with checking the first element and find it immediately, then the worst case performance of search improves to O(n^2) Which of the following is true about searching elements in an ordered array? You cannot use binary search on an ordered array so the performance is O(n) If there are no holes in the array and the elements are all next to each other, then the performance for search improves to…
2. An interpolation search assumes that the data in an array is sorted and uniformly distributed.Whereas a binary search always looks at the middle item in an array, an interpolation searchlooks where the sought-for item is more likely to occur. For example, if you searched yourtelephone book for Victoria Appleseed, you probably would look near its beginning ratherthan its middle. And if you discovered many Appleseeds, you would look near the lastAppleseed. Instead of looking at the element a[mid] of an array a, as the binary search would,an interpolation search examines a[index], where p = (desiredElement - a[first]) / (a[last] - a[first]) index = first + [(last – first) × p]Implement an interpolation search of an array. For particular arrays, compare the outcomesof an interpolation search and of a binary search. Consider arrays that have uniformlydistributed entries and arrays that do not. Modify and save the file asSearchComparerYourlastname.java.
9).An array of integers nums sorted in ascending order, find the startingand ending position of a given target value. If the target is not found in thearray, return [-1, -1]. For example:Input: nums = [5,7,7,8,8,8,10], target = 8Output: [3,5]Input: nums = [5,7,7,8,8,8,10], target = 11Output: [-1,-1]. Please weite your Code.
array unordered Arr has unsorted integers. SortedArr is an integer array. SortedArr performs which task better than unsortedArr? Use the fastest algorithms. Inserting a new element II Searching for a given element III Calculating the mean of the elements (A) I alone (B) II alone (C) III alone (D) I and II alone (E) I, II, and III
Given a sorted array of n integers that has been rotated an unknownnumber of times, write code to find an element in the array. You may assume that the array wasoriginally sorted in increasing order.EXAMPLElnput:find5in{15, 16, 19, 20, 25, 1, 3, 4, 5, 7, 10, 14}Output: 8 (the index of 5 in the array)
Java The program is supposed to:a) allocate storage for an array of integers of a size specified by the userb) fill the array partially with increasing values (number of values chosen by the user)c) check that the item at a user specified index position can be removed, maintaining order of other elementsd) check that a new item can be added at a user specified index position, also maintaining order of otherelements.the code is here: