I ONLY NEED AN EXPLANATION OR A SCRIPT FOR THE GIVEN SOLUTION.SKIP IF YOU ALREADY DID THIS Given data:Height of table is: h= 0.60 mHorizontal velocity is: v= 2.4 m/sConsider the figure as shown below:hThe vertical component of the ball's initial velocity is zero i.e., v₁, = 0.XThe time required for the pool ball to fall on the ground is:h=v₁t++ 17/181²20.60 m = (0)t++1 (9.8 m/s²)+²(4.9 m/s² )t² = 0.60 mt = 0.349927 st≈ 0.350 sThe horizontal distance between the table's edge and the ball's landing location is:x = vt= (2.4 m/s)(0.350 s)= 0.840 mPLEASE EXPLAIN THESOLUTION PROVIDEDABOVE

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Given data: Height of table is: h= 0.60 m Horizontal velocity is: v= 2.4 m/s Consider the figure as shown below: h x The vertical component of the ball's initial velocity is zero i.e., v₁, = 0. The time required for the pool ball to fall on the ground is: 1 h=v₁t+ = /gt² 0.60 m = (0)t + ¹ (9.8 m/s²)t² ½

Given data: Height of table is: h= 0.60 m Horizontal velocity is: v= 2.4 m/s Consider the figure as shown below: h x The vertical component of the ball's initial velocity is zero i.e., v₁, = 0. The time required for the pool ball to fall on the ground is: 1 h=v₁t+ = /gt² 0.60 m = (0)t + ¹ (9.8 m/s²)t² ½

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter4: Motion In Two And Three Dimensions

Section: Chapter Questions

Problem 36P: An airplane flying horizontally with a speed of 500 km/h at a height of 800 m drops a crate of...

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