Given: disk 1 2 3 Trial 1 Table W1: Calculation of the moment of inertia of the disks outer radius 8.80 ± 0.02 [cm] Icm (kg-m²) 3996*10^-8 inner radius 0.55 0.02 [cm] mass 102.8 ± 0.1 [g] 2.700.02 [cm] 8.70 ± 0.02 [cm] 256.4 ± 0.1 [g] 0, (rad) w (rad/s) t(s) (rad) 4.00 [s] -181.78 [rad] -26.36 [rad/s] 9.35 [s] -309.08 [rad] 1062*10^-6 Trial Au (rad/s) | At (8)||0| (rad/s²) | |7| (N-m) 1 4.69 5.35 0.8766 3503x10^-8 Unkown: Verification of conservation of energy wf (rad/s) -21.67 [rad/s] Table W4: Data for verification of conservation of energy Trial K; (J) Kƒ (J) | AEmech (J) | Wfriction (J) 1
Given: disk 1 2 3 Trial 1 Table W1: Calculation of the moment of inertia of the disks outer radius 8.80 ± 0.02 [cm] Icm (kg-m²) 3996*10^-8 inner radius 0.55 0.02 [cm] mass 102.8 ± 0.1 [g] 2.700.02 [cm] 8.70 ± 0.02 [cm] 256.4 ± 0.1 [g] 0, (rad) w (rad/s) t(s) (rad) 4.00 [s] -181.78 [rad] -26.36 [rad/s] 9.35 [s] -309.08 [rad] 1062*10^-6 Trial Au (rad/s) | At (8)||0| (rad/s²) | |7| (N-m) 1 4.69 5.35 0.8766 3503x10^-8 Unkown: Verification of conservation of energy wf (rad/s) -21.67 [rad/s] Table W4: Data for verification of conservation of energy Trial K; (J) Kƒ (J) | AEmech (J) | Wfriction (J) 1
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I need help with answering rotation questions where in an experiment, a disk (Disk1) was dropped on a rotary motion sensor. Please show complete solutions and I will give thumbs up. Thank you.
![Given:
disk inner radius
1
0.55 0.02 [cm]
2.70
2
3
Table W1: Calculation of the moment of inertia of the disks
outer radius
Icm (kg-m²)
8.80 ± 0.02 [cm]
3996*10^-8
Trial
1
0.02 [cm] 8.70 0.02 [cm]
0; (rad)
w; (rad/s)
4.00 [s] -181.78 [rad] -26.36 [rad/s]
mass
102.8 ± 0.1 [g]
256.4 ± 0.1 [g]
te (s)
(rad)
9.35 [s] -309.08 [rad]
1062*10^-6
Trial Au (rad/s) | At (s) | |n| (rad/s²) | |7| (N-m)
1
4.69
5.35
0.8766
3503x10^-8
Unkown:
Verification of conservation of energy
wf (rad/s)
-21.67 [rad/s]
Table W4: Data for verification of conservation of energy
Trial || Kį (J) | Kƒ (J)| AEmech (J) | Wfr
Vfriction (J)
1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F30d3a86f-0b2d-4e21-87c8-7843c994955a%2Fdc72a7fb-354b-48eb-b571-b19e0b44a37f%2Fi9mfdw_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Given:
disk inner radius
1
0.55 0.02 [cm]
2.70
2
3
Table W1: Calculation of the moment of inertia of the disks
outer radius
Icm (kg-m²)
8.80 ± 0.02 [cm]
3996*10^-8
Trial
1
0.02 [cm] 8.70 0.02 [cm]
0; (rad)
w; (rad/s)
4.00 [s] -181.78 [rad] -26.36 [rad/s]
mass
102.8 ± 0.1 [g]
256.4 ± 0.1 [g]
te (s)
(rad)
9.35 [s] -309.08 [rad]
1062*10^-6
Trial Au (rad/s) | At (s) | |n| (rad/s²) | |7| (N-m)
1
4.69
5.35
0.8766
3503x10^-8
Unkown:
Verification of conservation of energy
wf (rad/s)
-21.67 [rad/s]
Table W4: Data for verification of conservation of energy
Trial || Kį (J) | Kƒ (J)| AEmech (J) | Wfr
Vfriction (J)
1
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