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- In this task, you can use all functions of R to help you. In a recently conducted study, it was tested whether there is a connection between job satisfaction and income and seniority in nine randomly selected employees. The value attached to job satisfaction is each employee's own assessment, where 1 describes low satisfaction and 10 high satisfaction. Material: annual income (per thousand dollars) years spent in job satisfaction 47 8 5.6 42 4 6.3 54 12 6.8 48 9 6.7 56 16 7.0 59 14 7.7 53 10 7.0 62 15 8.0 66 22 7.8 The result was the material below a) Fit a two-explainer linear regression model to the data with R's function lm(). What happens to job satisfaction as the number of years increases? For explanatory variables, can the null hypothesis that the corresponding regression coefficient is equal to zero be rejected? b) It is assumed that job satisfaction is only related to years in that job. Estimate the regression parameters using R software. What…8. Areal estate company wants to study the relationship between Home price (in OMR 1000) and the following variables: Floor size (in 100 square feet) (X 1 ) Type of Heating (X 2 =1 if electricity and X 2 =0 , Gas, Location of home in town and X 3 =0 , if in village). Use this to answer the following questions: Then the P-value for testing Ho: B2=0 against H 1 :B 2 not =0 is A. 0.2623 B. 0.0073 C. 0.0037 D. 0.1312 E. NoneThe Greer Tire company manufactures a new steel-belted radial tire to be sold through a national chain of discount stores. Because the tire is a new product, Greer’s managers believe that the mileage guarantee offered with the tire will be an important factor in the acceptance of the product. Let X = miles that the tires last: X~N(60,000 2,500) Find the mileage guarantee that ensures this company will repair no more than 15% of its product for free. Assume the distribution of tire mileage is normal.
- A researcher wants to explore the differences in health effects from two different types of sugar. She hypothesizes that artificial sweetener has lower long term health benefits than natural sugar. What is her null hypothesis? Fill in the blank. H0: μArtificalSweetener__________ μNaturalSugar Group of answer choices a) Less than b) Less than or equal to c) Greater than d) Greater than or equal to2. Jim and Catherine are again interested in adjusting the 0-1 variables from Case 2.2 so that theycan examine different scenarios. However, theyrealize that the number of combinations of thetwo 0-1 variables they have control of, low-endversus high-end and mildly aggressive marketing versus very aggressive, is a small number,2×2 = 4. Therefore, they want you to use aRISKSIMTABLE function, with an index from 1to 4, so that a single @RISK run with 4 simulations can be made. You will have to use lookupfunctions so that the two 0-1 variables changeappropriately as the index of RISKSIMTABLEvaries from 1 to 4. As for the third 0-1 variable, whether the competition will introducea competing product, they want you to modelthis probabilistically, using a RISKBERNOULLIfunction with parameter 0.3. This simply indicates that there is a 30% chance of a competingproductA governmental agency determines that the Lorentzcurves for the distribution of income for dentists andcontractors in a certain state are given by the functionsL1 (x) = 2 + x1.35, L2 (x) = 0.12+ 0.9x, andrespectively.For which profession is the distribution of income morefairly distributed?
- Determine all the critical points for the function ?(?) = √?? (?? − ?)A researcher collects data that represents the average number of hours of sleep in the last two nights by 8 depressed patients and 9 non-depressed patients. The researcher is interested in whether the two groups reliably differ in the amount of sleep they get. Use Jamovi to calculate t-obt and the p value.We have a table of cities and temperatures. Use 1 Way fixed-effects ANOVA tocalculate the F value showing your work.city temperatureOrlando 70Orlando 65Orlando 60Orlando 65Dallas 75Dallas 65Dallas 60Dallas 60Chicago 50Chicago 50Chicago 40Chicago 40The null hypothesis is H0 : µOrlando = µDallas = µChicago
- Five different oat varieties were planted in each of the four fields.The following crops were obtained oat variety field field field field 1 2 3 4 1 296 357 340 348 2 402 390 420 335 3 345 324 358 308 4 360 322 336 270 5 324 339 357 308 Test whether there is a difference in the amount of harvest based on the data(a) between fields. (b) between varieties. DO NOT use ready-made functions of R or any other software for tests. Instead, you can use R to calculate quantiles, sample means, sample standard deviations and p-values. If no significance level is given in the task, use the usual/usual significance levels.Pet Owners A study of pet owners showed the following information concerning the ownership of the dogs and cats. At =α0.10 , is there a relationship between the number of people in a family and dog or cat ownership? Use the critical value method with tables. 1 person 2 people 3 people 4 or more people Dog 5 15 10 25 Cat 10 15 15 15 1)State the hypotheses and identify the claim. H0: Pet ownership is ▼(DEPENDANT ON or INDEPENDANT OF?) the number of people living in the household. (CLAIM OR NOT CLAIM?) H1 : Pet ownership is (DEPENDANT ON or INDEPENDANT OF?) the number of people living in the household. (CLAIM OR NOT CLAIM?) 2. Find the critical value 3. Compute the test value: X^2= 4. Reject or Do not reject the null hypothesis 5. Summarize: Is there or is there not enough evidence to reject the claim?Is there or is there not enough evidence to support the claim?2) A study was conducted to examine four methods for tutoring in mathematics. Four studentswere randomly assigned to each method, and a pretest score (x1) was obtained before tutoringbegan. The response of interest is a posttest score (y), and dummy variables x2, x3, and x4, werecreated for methods 1, 2, and 3, respectively. Variables x5, x6, and x7, are crossproductvariables for methods 1, 2, and 3, respectively, multiplied by x1. The results from fitting threeregression models to these data are attached to the end of the exam. Since the posttest score isharder than the pretest, it is not unusual for x1 values to be higher than y values. a) Assuming that the parallelism assumption is valid, test for equality of the adjustedgroup means, using alpha = .05. Write the null and alternative hypotheses, calculate an F statisticvalue, compare it to a tabled value and state your conclusion from the hypothesis test. b) Use the fact that the sample mean of x1 is 4.44, and the printout from…