6) Given i and j, two variables oftype double. Which of thefollowing statements declares adouble variable s and assigns² + j² to it, if i and j areassigned positive values?&& j>0)double s =Meth.pow(i,2) + Math.pow(j,2) ;double s-Math.sqrt(i,2)+Math.sgrt(j,2);rMath. pow(i,2)>0 && Math.pow(j,2) >0)le s-Math.pow(i,2) - Math.pow(0,2):-Mech.pow(,2)-Math.pow(,2)ctivato to Se

Correct Answer: (a) if(i>0 && j>0) double…

Given i and j, two variables of type double. Which of the following statements declares a double variable s and assigns i² + j² to it. if i and j are double s =Math.pow(i,2) + Math.pow(j,2); assigned positive values? acuble s -Math.sqrt(i, 2)+Math.sqrt(j,2); :(Math.pow (1,2) >0 s& Math.pow(j,2)>0) -Mata.powc,2) - Math.pcw.2)a ctiv

Given i and j, two variables of type double. Which of the following statements declares a double variable s and assigns i² + j² to it. if i and j are double s =Math.pow(i,2) + Math.pow(j,2); assigned positive values? acuble s -Math.sqrt(i, 2)+Math.sqrt(j,2); :(Math.pow (1,2) >0 s& Math.pow(j,2)>0) -Mata.powc,2) - Math.pcw.2)a ctiv

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Blackout Math is a math puzzle in which you are given an incorrect arithmetic equation. The goal of the puzzle is to remove two of the digits and/or operators in the equation so that the resulting equation is correct. For example, given the equation 6 - 5 = 15 ^ 4/2we can remove the digit 5 and the / operator from the right-hand side in order to obtain the correct equality 6 - 5 = 1 ^ 42. Both sides of the equation now equal to 1. Observe how removing an operator between two numbers (4 and 2) causes the digits of the numbers to be concatenated (42). Here is a more complicated example: 288 / 24 x 6 = 18 x 13 x 8 We can remove digits and operators from either side of the equals sign (either both from one side, or one on each side). In this case, we can remove the 2 from the number 24 on the left-hand side and the 1 from the number 13 on the right-hand side to obtain the correct equality 288 / 4 x 6 = 18 x 3 x 8 Both sides of the equation now equal to 432. Here is another puzzle for you…