Given P=10psi T= -20°F We know that, Dens?ty of air at a state Ps given by, P %3D RT P=(10psi) (144 f/Lft) I=(-20°F+ 46o)°R = 440°R $ R= 1716 ft.llbf Islug.°R where 1440 lbf/ft? %3D There fore, 2. 1440 lbf/ft (1716 ft. bf/slug.°R) (440°R) :0.00191 slylft? %3D
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how to solve for the density of air? can anyone explain the process and how to get the value of Rspecific gas constant (1716 ft.lbf/slug.R)? I'm really confused. Thank you
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