222=6068.5-745CGiven that PCA) = 1/5, PCB) = 1/3, PCC) = 2/5, PCAIB) = 1/2and PCBNC) = 0a) find PCAIB)B) find PCAUB)C) find PC ANBNC)

P(A)=1/5 P(B)= 1/3 P(C)= 2/5 P(A|B)=1/2 P(B∩C)=0

Answered: Given that PCA) = 1/5, PCB) = 1/3, PCCJ…

Given that PCA) = 1/5, PCB) = 1/3, PCCJ = 2/6, PCAIB) = 1/2 and PCBNC) = 0 a) find PCAIB) B) find PCAUB) C) find PC ANBNC)

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter10: Sequences, Series, And Probability

Section: Chapter Questions

Problem 60RE

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Question

22
2=
60
68.5-7
45
C
Given that PCA) = 1/5, PCB) = 1/3, PCC) = 2/5, PCAIB) = 1/2
and PCBNC) = 0
a) find PCAIB)
B) find PCAUB)
C) find PC ANBNC)

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