Given that P(n) is the equation 1+3+5+7++ (2n − 1) = n², where n is an integer such that n ≥ 1, we will prove that P(n) is true for all n ≥ 1 by induction. (a) Base case: i. Write P(1). ii. Show that P(1) is true. In this case, this requires showing that a left-hand side is equal to a right-hand side. (b) Inductive hypothesis: Let k≥ 1 be a natural number. Assume that P(k) is true. Write P(k). (c) Inductive step: i. Write P(k+ 1). ii. Use the assumption that P(k) is true to prove that P(k+1) is true. Justify all of your steps.

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter8: Sequences, Series, And Probability
Section8.5: Mathematical Induction
Problem 42E
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Given that P(n) is the equation 1+3+5+7+...+(2n − 1) = n², where n is an integer
such that n ≥ 1, we will prove that P(n) is true for all n ≥ 1 by induction.
Base case:
i. Write P(1).
ii. Show that P(1) is true. In this case, this requires showing that a left-hand side is equal to a
right-hand side.
(b) Inductive hypothesis: Let k ≥ 1 be a natural number. Assume that P(k) is true. Write P(k).
(c) Inductive step:
i. Write P(k+1).
ii. Use the assumption that P(k) is true to prove that P(k+1) is true. Justify all of your
steps.
Transcribed Image Text:Given that P(n) is the equation 1+3+5+7+...+(2n − 1) = n², where n is an integer such that n ≥ 1, we will prove that P(n) is true for all n ≥ 1 by induction. Base case: i. Write P(1). ii. Show that P(1) is true. In this case, this requires showing that a left-hand side is equal to a right-hand side. (b) Inductive hypothesis: Let k ≥ 1 be a natural number. Assume that P(k) is true. Write P(k). (c) Inductive step: i. Write P(k+1). ii. Use the assumption that P(k) is true to prove that P(k+1) is true. Justify all of your steps.
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