Given that resultant moment vector along the negative x-axis is 500 Nm, find the value of F. 300 mim 200 mm 150 mm 400 mm 200 mm
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Given that resultant moment
along the negative x-axis is 500 Nm, find
the value of F
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Solved in 3 steps with 4 images
- Determine the orientation of the main barycentric axes and the corresponding moment values of inertia of the illustrated surface (Figure 6.19) using the Mohr circle. (Are given Ix = 6.16 x 106 mm4 e Iy = 60.9 x 106 mm4 ).A force F having a magnitude of F = 100 N actsalong the diagonal of the parallelepiped. Determine themoment of F about the point A, using MA = rB x F andMA = rC x F.Determine the solution for the bar forces in the truss shown when P = 1 kip and x = 5 ft: AC = -1732.05 AB = 2000 BC = -866.03 BD = 2500 DC = 2020.73 EC = -3175.43
- Replace the loading system by an equivalent resultant force and couple moment acting at point ?. Length AB = 1m Length BC = 2m F1 = 80 N F2 = 60 N F3 = 120 N Angle with respect to x-axis = 32 degrees Moment couple = 195 NmShould the moment at ED be 256.95? and i am not seeing you calculate that moment at EFor the beam shown, determine the rotation at point C by placing a unit couple at C in the virtual system.
- Calculate the value of the moment reaction at A of the beam shown below. If the direction is counterclockwise, affix negative sign betore the numerical value. Answer to the nearest whole number, units in kN-m. Use Moment Distribution Method.The magnitude of the force Qis 736 N. Determine the magnitude of the moment (Nm) of Q about point C. Round off only on the final answer expressed in 3 decimal places.Given a 2-D force system with geometry as shown. Find the magnitude of the equivalent couple moment (Nm) acting at O if P = 507 N , Q = 382 N, and T = 451 N . Round off only on the final answer expressed in 3 decimal places. Instead of units, indicate the direction of moment: use CW if clockwise , CCW if counterclockwise.
- Find the Laplace transform of f(t)={0, t<3 ={t2−6t+13, t≥3 F(s)=Calculate the moments in the frame given below using moment distibution method and fraw moment diagram of the frame. (Take value of EI& as 80kN-m^3)can you do this follow up question please ; c) the value of the maximum bending moment in the beam. Enter your answer in kNm to three decimal places. Note: when deriving internal moment equations, use the following orientation of x coordinate: Segment AB: x changes from 0 at support A to a at support B. After making the cut, keep the part of the beam left from the cut. Segment BC: x changes from a at support B to L at point C, where L = a + b. After making the cut, keep the part of the beam right from the cut, i.e. distance from point C to the cut is equal L-x.