Given that sine = -1/2 and e lies in quadrant IV, find the following value. cose -2

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.3: Trigonometric Functions Of Real Numbers
Problem 43E
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Refer to the table below if needed.
Second Quadrant
Third Quadrant
Fourth Quadrant
sin(1800 -e) = sine
sin(180• +e) = - sing
sin(360° -e) = - sing
cos(180° -e) = - cose
cos(1800 +e) = - cose
cos(360° -e) = cose
tan(1800 -e) = - tane
tan(180° +e) = tane
tan(360° -e) = - tane
cot(180° -e) = - cote
cot(1800 +e) = cote
cot(360° -e) = - cote
sec(180° -e) = - sece
sec(180° +e) = - sece
sec(360° -e) = sece
csc(180° -e) = csce
csc(1800 +e) = - cSce
csc(360° -e) = - CSCA
Given that sine = -1/2 and e lies in quadrant IV, find the following value.
cose
-2
-V3/2
V3/2
Transcribed Image Text:Refer to the table below if needed. Second Quadrant Third Quadrant Fourth Quadrant sin(1800 -e) = sine sin(180• +e) = - sing sin(360° -e) = - sing cos(180° -e) = - cose cos(1800 +e) = - cose cos(360° -e) = cose tan(1800 -e) = - tane tan(180° +e) = tane tan(360° -e) = - tane cot(180° -e) = - cote cot(1800 +e) = cote cot(360° -e) = - cote sec(180° -e) = - sece sec(180° +e) = - sece sec(360° -e) = sece csc(180° -e) = csce csc(1800 +e) = - cSce csc(360° -e) = - CSCA Given that sine = -1/2 and e lies in quadrant IV, find the following value. cose -2 -V3/2 V3/2
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