Given the arrangement of charged particles shown in the figure below, find the net electrostatic force on the Q2 = 8.00-nC charged particle located at the origin. (Express your answer in vector form. Assume Qi = -20.00 nC and Q3 = 2.00 nC.) (-3.50 cm, 0) (1.50 cm, 0)

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Chapter25: Gauss’s Law
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Given the arrangement of charged particles shown in the figure below, find the net electrostatic force on the Q2 = 8.00-nC
charged particle located at the origin. (Express your answer in vector form. Assume Q1 = -20.00 nC and Q3 = 2.00 nC.)
%3D
(-3,50 cm, 0)
(1.50 cm, 0)
Transcribed Image Text:Given the arrangement of charged particles shown in the figure below, find the net electrostatic force on the Q2 = 8.00-nC charged particle located at the origin. (Express your answer in vector form. Assume Q1 = -20.00 nC and Q3 = 2.00 nC.) %3D (-3,50 cm, 0) (1.50 cm, 0)
estion 6.
Given the arrangement of charged particles in the figure below, find the net electrostatic force on the q =5.55-uC charged
particle. (Assume q2 = 16.33 µC and q3 = -17.12 µc. Express your answer in vector form.)
IpC = 10*C Q= S.5se-bC
5.5uC-6,55e6 Q = 1,63)E-5
N
%3D
1000 000
B,
(1.00 cm, 1.00 em
Qz = -1.712 E-5
Subjeut
4.
A,
3.le-Zn
= -0.02 m
01
1200 cm, Da
A,
B, = 0.01m
k= 8.99169
%3D
(0, -1.00 cm)
Cy'e -0.이m
(7.04228
Subjeut)
Do tane blin AtB = 31le-2m
V
3.1le-2m
- ,02- .01)² + CO- .01)²
Do tance brun A tc = 2.24e-2M
V(-.02 - 0)² +(0 - (- .01))*
%3D
All the forces on q, are
on I
Cos B= Cos a
Sin d if
VTO
2on I
8.16e2
%3D
(3.1be-2) ²
F2on= kl-1.712 e-5* 5.5te-6|
(2.244e-2)2
1,70€3
3on 1
6
Transcribed Image Text:estion 6. Given the arrangement of charged particles in the figure below, find the net electrostatic force on the q =5.55-uC charged particle. (Assume q2 = 16.33 µC and q3 = -17.12 µc. Express your answer in vector form.) IpC = 10*C Q= S.5se-bC 5.5uC-6,55e6 Q = 1,63)E-5 N %3D 1000 000 B, (1.00 cm, 1.00 em Qz = -1.712 E-5 Subjeut 4. A, 3.le-Zn = -0.02 m 01 1200 cm, Da A, B, = 0.01m k= 8.99169 %3D (0, -1.00 cm) Cy'e -0.이m (7.04228 Subjeut) Do tane blin AtB = 31le-2m V 3.1le-2m - ,02- .01)² + CO- .01)² Do tance brun A tc = 2.24e-2M V(-.02 - 0)² +(0 - (- .01))* %3D All the forces on q, are on I Cos B= Cos a Sin d if VTO 2on I 8.16e2 %3D (3.1be-2) ² F2on= kl-1.712 e-5* 5.5te-6| (2.244e-2)2 1,70€3 3on 1 6
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