given the chunk codes, what will be printed on screen? intx=5; x= x+6; x++; print("%d", x);
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Q: Block size = 4 bits Hash size = 4 bits Encryption function: Divide the key into two halves: LK and…
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A: Code and output given below:
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- Given a binary file written using struct.pack() with the given format, return the number of bytes in the file and the number of bytes in each chunk.:param file_path::param format: a string with the format of the data in the struct:return: tuple with the number of bytes in file and the number of bytes written in each chunkUSE MODULE STRUCT AND OS IN PYTHONIn the variable-length record representation, a null bitmap is used to indicate if an attribute has the null value. a. For variable length fields, if the value is null, what would be stored in the offset and length fields? b. In some applications, tuples have a very large number of attributes, most of which are null. Can you modify the record representation such that the only overhead for a null attribute is the single bit in the null bitmap.In the AES Project, you should change the secret key of the AES by a dynamic key generated by RC4 after every 1024 bits, remember you should encrypt an image of 512*512*3 bytes, moreover, the used mode of operation should be CBC mode, Finally, use the attached figure to find the Number of cycles per byte and the encryption throughput?
- In the variable-length record representation, a null bitmap is used to indicateif an attribute has the null value. In some applications, tuples have a very large number of attributes, most of which are null. Can you modify the record representation such that the only overhead for a null attribute is the single bit in the null bitmap?Read the bash man or the info page, conduct some experiments, and respond to the following questions. questions: What is the procedure for exporting a function? What is the purpose of the hash builtin? What happens if the exec argument isn't a valid executable?Experimenting with AES-128 symmetric key cipher.using python PART 2: you will try to use "brute force" to decrypt an encrypted message, where you only have the first 96-bits of the 128-bit secret key (last 4 bytes of the secret key are missing!) The program should be called "findk", and should deal with two files that contain the encrypted text as a stream of bytes and the first 96-bits of the key, respectively. The program should print out on standard output the missing 4 bytes of the key in hexadecimal, the decrypted message and the time it took to find the correct key.o To test this part, here is the encrypted file (ciphertext2.dat), and the first 96-bits of the key (partial-key.dat) Hint: the original message starts with the word "Salam". Answer you provided .from Crypto.Cipher import AESdef revpad(s):"""This function is to remove padding.parameters:s:strstring to be reverse padded"""k = ord(s[-1])temp = 0 # temporary variable to check paddingfor i in range(1, k): # for loop to…
- New JAVA Code can only be added to the Order.java files after line 17. Lines 1-17 can NOT be changed in any way.What is the difference between a symbolic link and the destination file in terms of file size?Consider the following code chunk and output and note that NA appears in the output of lm(). X1 <- rnorm(1e2) X2 <- X1 + 3 Y <- X1 + X2 + rnorm(1e2) lm(Y ~ X1 + X2) Call: lm(formula = Y ~ X1 + X2) Coefficients: (Intercept) X1 X2 2.979 2.019 NA Which of the following statements are correct?a) Perfectly correlated regressors X1 and X2 are used.b) lm() excludes X2 from the regression so that there is a least squares solution. c) NA indicates that the model fit to the data is perfect.
- with open('./small_network_data.txt') as file: num_u = int(file.readline().strip()) adj_mat = [[0 for j in range(num_u)] for i in range(num_u)] print() for line in file: user1, user2 = [int(x) for x in line.strip().split()] adj_mat[user1][user2] =1 adj_mat[user2][user1] = 1 Simi_mat = [[0 for j in range(num_u)] for i in range(num_u)] for row in range(num_u): for col in range(num_u): for other_row in range(num_u): if adj_mat[row][other_row] == 1 and adj_mat[other_row][row] ==1: continue if adj_mat[row][col]==1 and row != other_row and adj_mat[other_row][col] ==1: Simi_mat[row][other_row] +=1 reommended_rn = [] for row in Simi_mat: reommended_rn.append(row.index(max(row))) for row in reommended_rn: print(row) ________________________ the last step is missing in the above code. Please check and help me to complete to get final output.write a bash shell script to display the grade of a student according to his marks enteredStarting out with hadoop and I need to find the 8-bit XOR checksum of all bytes from 1000000000 till 1000000999 (inclusive) with the offset in a file called "bigdata" in a directory called d1. How would I do this in Java using the HDFS API?