Given the circuit below and the associated set of voltages and currents, the real Power developed by the dependent voltage source is V3 1Ω j2 N + 1Ω j3 N 12 Ωξ +. 39 I, -j16 NF V, = 150 /0° V I = (-26 – j52) A I, = (-2 + j6) A V1 = (78 – j104) V %3D | V2 = (72 + j104) V %3D %3D V3 = (150 – j130) V I = (-24 – j58)A %3D Copyright © 2011 Pearson Education, Inc. publishing as Prentice Hall Select one: a. None of these

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter2: Fundamentals
Section: Chapter Questions
Problem 2.17MCQ: Consider the load convention that is used for the RLC elements shown in Figure 2.2 of the text. A....
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ols.liu.edu,lb/mod/quiz/attempt
Given the circuit below and the associated set of
voltages and currents, the real Power developed
by the dependent voltage source is
1Ω
j2 N +
1Ω
j3 N
12 Ωξ
+
39 I,
-j16 N
V, = 150 /0° V
V1 = (78 – j104) V
I = (-26 – j52) A
V2 = (72 + j104) V
I, = (-2 + j6) A
V3 = (150 – j130) V
I = (-24 – j58) A
Copyright © 2011 Pearson Education, Inc. publishing as Prentice Hall
Select one:
a. None of these
b. 2500 W
c. 5850 W
d. 8000 W
Transcribed Image Text:ols.liu.edu,lb/mod/quiz/attempt Given the circuit below and the associated set of voltages and currents, the real Power developed by the dependent voltage source is 1Ω j2 N + 1Ω j3 N 12 Ωξ + 39 I, -j16 N V, = 150 /0° V V1 = (78 – j104) V I = (-26 – j52) A V2 = (72 + j104) V I, = (-2 + j6) A V3 = (150 – j130) V I = (-24 – j58) A Copyright © 2011 Pearson Education, Inc. publishing as Prentice Hall Select one: a. None of these b. 2500 W c. 5850 W d. 8000 W
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