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Given the code shown answer the following: a) What is the function of this program? b) compile the code and show its assembly. c) Draw the flowchart that represent the function above. #include using namespace std; int main () int T, N, sum ; cin >> T ; for ( int i = 1; i <= T ; ++i) { cin >> N ; sum = N /2*( N /2 + 1); if (N % 2 == 0) // Gives the solution. cout << "the sum is " << sum << endl ; else cout << "no sum" << endl; } return 0;

Given the code shown answer the following: a) What is the function of this program? b) compile the code and show its assembly. c) Draw the flowchart that represent the function above. #include using namespace std; int main () int T, N, sum ; cin >> T ; for ( int i = 1; i <= T ; ++i) { cin >> N ; sum = N /2*( N /2 + 1); if (N % 2 == 0) // Gives the solution. cout << "the sum is " << sum << endl ; else cout << "no sum" << endl; } return 0;

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Given the code shown answer the following: a) What is the function of this program? b) compile the code and show its assembly. c) Draw the flowchart that represent the function above. 1 #include <iostream> 2 3 using namespace std; 4 5 int main () 6- { int T, N cin >> T ; for ( int i = 1; i <= T; ++ i ) { cin >> N ; sum = N /2*( N /2 + 1) ; if (N % 2 == 0) 7 , sum ; 8. 10 11 12 13 14 15 // Gives the solution. 16 cout << "the sum is " <« sum << endl ; 17 18 else 19 cout << "no sum" << endl; } return 0; 20 21 22 23
Transcribed Image Text:Given the code shown answer the following: a) What is the function of this program? b) compile the code and show its assembly. c) Draw the flowchart that represent the function above. 1 #include <iostream> 2 3 using namespace std; 4 5 int main () 6- { int T, N cin >> T ; for ( int i = 1; i <= T; ++ i ) { cin >> N ; sum = N /2*( N /2 + 1) ; if (N % 2 == 0) 7 , sum ; 8. 10 11 12 13 14 15 // Gives the solution. 16 cout << "the sum is " <« sum << endl ; 17 18 else 19 cout << "no sum" << endl; } return 0; 20 21 22 23
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