Given the expression let x = 8.965; what is the value of x.toPrecision(2)?
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Given the expression let x = 8.965; what is the value of x.toPrecision(2)?
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- Given the following function, what happens if a[] contains just one element that doesn't match val? int binarySearch(int a[], int first, int last, int val){ if (first > last) return -1; int middle = (first + last) / 2; if (a[middle] == val) return middle; if (a[middle] < val) return binarySearch(a, middle+1, last, val); else return binarySearch(a, first, middle-1, val);} Group of answer choices binarySearch never calls itself again and terminates (recursion never happens) binarySearch calls itself once then terminates (recursion happens once) binarySearch calls itself twice then terminates (recursion happens twice) binarySearch calls itself 3 times then terminates (recursion happens 3 times)Implement a commonly used hash table in a program that handles collision using linear probing. Using (K mod 13) as the hash function, store the following elements in the table: {1, 5, 21, 26, 39, 14, 15, 16, 17, 18, 19, 20, 111, 145, 146}.Consider the idea of implementing modular hashing for integer keys with thecode (a * k) % M , where a is an arbitrary fixed prime. Does this change mix up thebits sufficiently well that you can use nonprime M?
- Suppose you generate the following RSA key pairs:• p = 37199• q = 49031• N = p · q = 1823904169• (p − 1) · (q − 1) = 1823817940• e = 65537 (for encryption)• d = 1578812933 (for decrption)Assuming a=01, b=02, . . . , z=26, and we group the digits in groups of three. (ii) If you receive strings of digits from a sender: 199770170, 1288754980, 324346846, 1370682962, decrypt the message.Let B be the set of all binary strings of length 8. {“00000000”, “00000001”, … “11111110”, “11111111”} How many elements of B have no adjacent digits with the same value? How many elements of B are palindromes? How many elements of B contain two or more 0s?python In simple uniform hashing, each key is assumed to have equal probability to map to any ofthe hashes in a given table of size m. Given an open-address table of size 100 and 2random keys, what is the probability that they hash to the same value? What is theprobability that they hash to different values?
- In Python, implement a hashing table data structure of size 20, which can cope with collisions. Thus, you must implement the closed collision system in its three modes: Linear scanQuadratic scanDouble hashing scan. For halt use halt(k)= (k mod (m - 1)) + 1, where m is the size of the table. The data to be managed are students from a certain university who have a 5-digit registration number and it is unique. In addition, the student has a name, age and address. Create a .txt file with 10 students (one for each line) and have them loaded into your program. Build a menu of options where you can: - Find a student and print his data if found and position in the table. Otherwise print a "Not Found" message.In Python, implement a hashing table data structure of size 20, which can cope with collisions. Thus, you must implement the closed collision system in its three modes: Linear scanQuadratic scanDouble hashing scan. For halt use halt(k)= (k mod (m - 1)) + 1, where m is the size of the table. The data to be managed are students from a certain university who have a 5-digit registration number and it is unique. In addition, the student has a name, age and address. Create a .txt file with 10 students (one for each line) and have them loaded into your program. Build a menu of options where you can: - Enter a new student. For this option, that only allows entering the 5-digit license plate and that random data is automatically generated for the name, age and address. Return the position where it was entered and if it is not possible to enter it, print a message that explains why the entry was not obtained.Write a program that animates quadratic probing,as shown in Figure . You can change the initial size of the hash-table in theprogram. Assume the load-factor threshold to be 0.8.
- The parity function is a very simple hash function producing a one-bit digest, which is 0 if the number of bits in the message is even and 1 if it is odd. Consider a communication system that uses 7 bits out of every byte to transmit data, and reserves the 8th bit (the one on the right) to transmit the parity of the other seven bits, for purposes of error checking. Below is the binary representation of some bytes that were transmitted using this system. For each one, tell whether there is a reason to suspect an error in transmission, giving the reason for your answer. 10110011 11101111 10101100 00110011develop a java program for universal Hashing , add approriate comments and explanations in your program give the above input and show the out put try hash function h4,4 with p=101 insert 8,22,36,75,61,13,83,58Can someone explain the normalize function for this hash table, and please provide comments for each line of code: void normalize(string & s) { string t = ""; for (int i = 0; i < s.length(); i++) { if (s[i] <= 'Z' && s[i] >= 'A') s[i] += ('a' - 'A'); if (s[i] <= 'z' && s[i] >= 'a') t+= s[i]; } s = t;} unsigned int hashStr(const string & s, int size) { unsigned int h = s[0]; for (int i = 1; i < s.length(); i++) //h = (h*i)+s[i]; //My hash h+=s[i]*26*i; //h+=s[i]; return h % size ;} int main(){ string word; string originalWord; int startTableSize; int endTableSize; int hashResult; do{ cout << "Enter the table starting size\n! to quit" << endl; cin >> startTableSize; cout << "Enter the table end size\n! to quit" << endl; cin >> endTableSize; cout << "Enter a word to hash\n!…