Given the following array: 65, 15, 129, 22, 12, 10, 239, 334, 10, 111, 180, 1, 2 What will be the array contents looking like in the following situations: 1) after calling the partition method three times in quick sort if pivot is the last element. 2) after the third iteration of the outer loop in insertion sort. 3) after the third iteration of the outer loop in Selection sort.
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Given the following array:
65, 15, 129, 22, 12, 10, 239, 334, 10, 111, 180, 1, 2
What will be the array contents looking like in the following situations:
1) after calling the partition method three times in quick sort if pivot is the last element.
2) after the third iteration of the outer loop in insertion sort.
3) after the third iteration of the outer loop in Selection sort.
Step by step
Solved in 4 steps with 4 images
- There is an array with the original content as follows61,12,95,89,65,23,45,78,57,33Now execute Insertion sort, from small to large, please write the contents of the array after Pass 3The code below computes the intersection (the number of entries shared by two arrays). It is assumed that neither array contains any duplicates. It computes the intersection by sorting one array (array b) and then iterating over array a to see if each value is in b (through binary search). What is its duration? nt intersection(int[] a, int[] b) {mergesort(b);}int intersect = 0;for (int x : a) {if (binarySearch(b, x) >= 0) {intersect++;return intersect; }}There is an array with the original content as follows61,12,95,89,65,23,45,78,57,33Now execute Bubble sort, from small to large, please write the contents of the array after Pass 3
- Write the state of the elements of each of the following arrays after each pass of the outermost loop of the selection sort algorithm has occurred (after each element is selected and moved into place).int[] numbers1 = {63, 9, 45, 72, 27, 18, 54, 36};int[] numbers2 = {37, 29, 19, 48, 23, 55, 74, 12};Select true or false for the statements below. Explain your answers if you like to receive partial credit Select true or false for the statements below. Explain your answers if you like to receive partial credit Which of the following is true about searching elements in an unordered array? With the data is unsorted, search is O(n) because if the element you are looking for is not there, you have to check every element in the array If you start at the end of the array and traverse to index 0, search improves to O(log n) because you only have to look at half of the array If you get lucky with checking the first element and find it immediately, then the worst case performance of search improves to O(n^2) Which of the following is true about searching elements in an ordered array? You cannot use binary search on an ordered array so the performance is O(n) If there are no holes in the array and the elements are all next to each other, then the performance for search improves to…True or False For each statement below, indicate whether you think it is True or False. If you use binary search on a sorted array, the performance at worst is O(log n) For the insert algorithm, if you use binary search to find the location to insert the new element, it will improve the overall performance of the algorithm to O(log n) For the update algorithm in a sorted array, all you have to do is use linear or binary search to find the element you want to change, and if you find it, you only need to change it to the new value Binary search can be used on an unsorted array Inserting elements into a sorted array is O(n) because you have to find the location to add the new element and then shift the remaining elements If the sorted array gets too large, the performance of binary search becomes O(n) For the delete algorithm, after you find the element to delete, you can make the algorithm run faster by replacing it with the last element in the array If you used binary search to…
- Below is how the arrays are represented ARRAY1[] = [1, 5, 6, 6, 9, 9, 9, 11, 11, 21] Here length of ARRAY1 is m. ARRAY2[] = [6, 6, 9, 11, 21, 21, 21] Here length of ARRAY2 is n. Array to be returned would be: ARRAY[] = [6, 9, 11, 21] ATTN : Further, please be reminded that you cannot use library functions to either sort and or perform the de-duplication operation. solve the problem in two ways In a separate implementation, code up a solution in such a way that your solution solves the problem with O(nlog(m)) time complexity 2 or O(mlog(n)) time complexity. Here log means to the base of 2. I’m sure you already know that the hint is to use Binary Search. In the form of sentences, as a comment in your code (at the bottom of your Solution2), you are required to suggest how can Solution2 be improved by leveraging the fact that both the arrays are already sorted. Suggest a solution so that your suggested solution can run linearly with O(m + n) time complexity. Your suggestion should be no…There is an array with the original content as follows61,12,95,89,65,23,45,78,57,33Now execute Quick sort, from small to large, please write the result in the array after the first SplitFollowing is the function for interpolation search. This searching algorithm estimates the position (index) of a key in array based on the elements in the first position and last position in the array, and the length of array. The array must be sorted in ascending order. Suppose array A contains the following 15 elements: A = [1, 3, 3, 10, 17, 22, 22, 22, 24, 25, 26, 27, 27, 28, 28] At first iteration, at which position (index) the element of 24 is estimated in array A? In which part of array (starting index and ending index) the searching should continue? How many iterations the searching are performed until the element of 24 is found? int InterpolationSearch(int x[], int key, int n) { int mid, min = 0, max = n-1; while(x[min] < key && x[max] > key) { mid = min + ((key-x[min])*(max-min)) / (x[max]-x[min]); if(x[mid] < key) min = mid + 1; else if(x[mid] > key) max = mid - 1; else return mid; } if…
- I hope this question will be solved in less than an hour and not taken from other sitesdata structure Given the following array: 65, 15, 129, 22, 12, 10, 239, 334, 10, 111, 180, 1, 2 What will be the array contents looking like in the following situations: 1) after calling the partition method three times in quick sort if pivot is the last element. 2) after the third iteration of the outer loop in insertion sort. 3) after the third iteration of the outer loop in Selection sort.Java-.Selection and insertion sort 3.a Show steps of selection sort for the given array. You may need to add more rows to the table. Selection Sort Initial value 3 2 7 5 4 8 9 10 1 Search 0 . . . end 3 2 7 5 4 8 9 10 1 Swap index 0 Search 1 . . . end . . . 3.b Show steps of insertion sort for the given array. You may need to add more rows to the table. Insertion Sort Initial value 3 2 7 5 4 8 9 10 1 , first item is sorted 3 2 7 5 4 8 9 10 1 , first 2 items are…Given the following array, what is the content of the array after Three passes of Insertion Sort? array: 44 12 50 3 40 23 Question 5 options: 3 12 44 50 40 23 12 44 50 3 40 23 12 3 23 40 44 50 12 3 44 50 40 23