Following array is being sorted by Radix sort. Two iterations are already completed, What will be the new sequence after running the third iteration. 1, 7, 10, 9420, 3221, 5622, 4127, 2030, 3138, 743, 577, 9680, 82, 4793, 2599
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- Given the following array, what is the content of the array after Three passes of Insertion Sort? array: 44 12 50 3 40 23 Question 5 options: 3 12 44 50 40 23 12 44 50 3 40 23 12 3 23 40 44 50 12 3 44 50 40 23Write the state of the elements of each of the following arrays after each pass of the outermost loop of the selection sort algorithm has occurred (after each element is selected and moved into place).int[] numbers1 = {63, 9, 45, 72, 27, 18, 54, 36};int[] numbers2 = {37, 29, 19, 48, 23, 55, 74, 12};Given the following array, what is the content of the array after Two passes of Radix Sort? array: 23 123 415 228 501 189 Question 6 options: 23 123 189 228 415 501 501 415 23 123 228 189 501 23 123 415 228 189 23 123 228 189 415 501
- JAVAUse array {"shall", "not", "perish", "from", "the", "earth"} to simulate selection sort. For each iteration, write down the value of initial value and index, the minimum value and its index, and then write down the array after each iteration.Given the following array, what is the content of the array after Two passes of Selection Sort? array: 44 12 50 3 40 23 Question 1 options: 12 3 40 23 44 50 40 12 23 3 44 50 3 44 12 40 23 50 12 44 3 40 23 50When using the Quick sort on the following array Complete the index of the following. pivot: Low: High: The indexes of the first swap low = high = %3D The index of the new pivot: 8 3. 2 4 6.
- Please Help me with This Question We are given two sorted arrays (all elements are in ascending order. We need to merge these two arrayssuch that the initial numbers (after complete sorting) are in the first array and the remaining numbers are inthe second array.Please run this code for n=6 for arrays 1,34,0,6,78,11 and n=5 for array 8,7,6,5,4 #include <stdio.h>void selection_sort(int arr[], int n) { if (n<=1) return ; int max_id=0; for(int i=0;i<n;i++) { if(arr[i]>arr[max_id]) max_id=i; } int temp=arr[max_id]; arr[max_id]=arr[n-1]; arr[n-1]=temp; selection_sort(arr,n-1); return;}Given the following array: 65, 15, 129, 22, 12, 10, 239, 334, 10, 111, 180, 1, 2 What will be the array contents looking like in the following situations: 1) after calling the partition method three times in quick sort if pivot is the last element. 2) after the third iteration of the outer loop in insertion sort. 3) after the third iteration of the outer loop in Selection sort.
- 1. Sorting• Begin by filling an array with random numbers:import numpy as npnp.random.seed(1012)DATASIZE = 1000MAX_VALUE = 10000000data = np.random.randint(0, MAX_VALUE, size=DATASIZE)• Write a function that is passed a numpy array. The function should walkthrough the array element-by-element, comparing the current element tothe next element. Swap if the next is smaller than the current – sortingthese two elements.• Write a second function that calls the above function n times, where n isthe number of elements (size) of the array. Pass the same numpy arrayeach time. 2. Bubble Sort• The sort from part 1 can be improved. If the data passed to be sorted isalready sorted, it still performs all of the work, as if the array was notsorted.Make two improvements:• Change the first function (the one that does the comparisons), so that it returns aboolean that states whether the array is sorted. Make use of that boolean to stopcalling the first function if the array is sorted.• Consider…1. Sorting• Begin by filling an array with random numbers:import numpy as npnp.random.seed(1012)DATASIZE = 1000MAX_VALUE = 10000000data = np.random.randint(0, MAX_VALUE, size=DATASIZE)• Write a function that is passed a numpy array. The function should walkthrough the array element-by-element, comparing the current element tothe next element. Swap if the next is smaller than the current – sortingthese two elements.• Write a second function that calls the above function n times, where n isthe number of elements (size) of the array. Pass the same numpy arrayeach time.The code below computes the intersection (the number of entries shared by two arrays). It is assumed that neither array contains any duplicates. It computes the intersection by sorting one array (array b) and then iterating over array a to see if each value is in b (through binary search). What is its duration? nt intersection(int[] a, int[] b) {mergesort(b);}int intersect = 0;for (int x : a) {if (binarySearch(b, x) >= 0) {intersect++;return intersect; }}
