Given the following data, where did 339 come from? Component Chemical formula Percentage Mass of component Mass of Hydrogen Mass of Carbon Propene C3H6 7% 7 kg =642×7=1 kg=642×7=1 kg =3642×7=6 kg=3642×7=6 kg Propane C3H8 52% 52 kg =844×52=9.45 kg=844×52=9.45 kg =3644×52=42.55 kg=3644×52=42.55 kg Butene C4H8 11.2 11.2 =856×11.2=1.6 kg=856×11.2=1.6 kg =4856×11.2=9.6 kg=4856×11.2=9.6 kg Butane C4H10 29.8 29.8 =1058×29.8=5.14 kg=1058×29.8=5.14 kg =4858×29.8=24.66 kg=4858×29.8=24.66 kg TOTAL =17.19 kg=17.19 kg =82.81 kg=82.81 kg Gross-Calorific value, GCV=339×%C+1427(%H−%O8)+22×%S GCV=339×82.81+1427(17.19−08)+22×0 GCV=52602.72 kJ/kg GCV=52.60272 MJ/kg

Given the following data, where did 339 come from? Component Chemical formula Percentage Mass of component Mass of Hydrogen Mass of Carbon Propene C3H6 7% 7 kg =642×7=1 kg=642×7=1 kg =3642×7=6 kg=3642×7=6 kg Propane C3H8 52% 52 kg =844×52=9.45 kg=844×52=9.45 kg =3644×52=42.55 kg=3644×52=42.55 kg Butene C4H8 11.2 11.2 =856×11.2=1.6 kg=856×11.2=1.6 kg =4856×11.2=9.6 kg=4856×11.2=9.6 kg Butane C4H10 29.8 29.8 =1058×29.8=5.14 kg=1058×29.8=5.14 kg =4858×29.8=24.66 kg=4858×29.8=24.66 kg TOTAL =17.19 kg=17.19 kg =82.81 kg=82.81 kg Gross-Calorific value, GCV=339×%C+1427(%H−%O8)+22×%S GCV=339×82.81+1427(17.19−08)+22×0 GCV=52602.72 kJ/kg GCV=52.60272 MJ/kg

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter31: Introduction To Analytical Separations

Section: Chapter Questions

Problem 31.12QAP

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A titrimetric method for the determination of calcium in limestone was tested by analysis of an NIST limestone containing 30.15% CaO. The mean result of four analyses was 30.26% CaO, with a standard deviation of 0.085%. By pooling data from several analyses, it was established that s   = 0.094% CaO.a. Do the data indicate the presence of a systematic error at the 95% confidence level?b. Do the data indicate the presence of systematic error at the 95% confidence level if no pooled value for s was available?
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A chemist obtained the following data for the percent compound Z in triplicates (n=3) of an insecticide preparation: 7.47, 6.98, and 7.27. Calculate the 90% confidence limit for the mean of the data assuming that only information about the precision of the method is the precision for the three data points. 7.24 ± 0.74% 7.24 ± 0.13% 7.24 ± 0.42% 7.24 ± 0.27%
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A titrimetric method for the determination of calcium in limestone was tested with the analysis of a NIST limestone containing 30.15% CaO. The mean of the four analyzes is 30.26% CaO with a standard deviation of 0.085%. From the data accumulated from many analyzes, s→ϭ=0.094% CaO was found.a) Do the data indicate the presence of systematic error at the 95% confidence level?b) When a value for ϭ is unknown, do the data show a systematic error at the 95% confidence level?
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An analyst obtained the following data for the percent compound Z in triplicates (n=3) of an insecticide preparation: 7.47, 6.98, and 7.27. Calculate the 90% confidence limit for the mean of the data assuming that only information about the precision of the method is the precision for the three data points.

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Component	Chemical formula	Percentage	Mass of component	Mass of Hydrogen	Mass of Carbon
Propene	C₃H₆	7%	7 kg	=642×7=1 kg=642×7=1 kg	=3642×7=6 kg=3642×7=6 kg
Propane	C₃H₈	52%	52 kg	=844×52=9.45 kg=844×52=9.45 kg	=3644×52=42.55 kg=3644×52=42.55 kg
Butene	C₄H₈	11.2	11.2	=856×11.2=1.6 kg=856×11.2=1.6 kg	=4856×11.2=9.6 kg=4856×11.2=9.6 kg
Butane	C₄H₁₀	29.8	29.8	=1058×29.8=5.14 kg=1058×29.8=5.14 kg	=4858×29.8=24.66 kg=4858×29.8=24.66 kg
TOTAL				=17.19 kg=17.19 kg	=82.81 kg=82.81 kg