Given the following function foo , which choice(s) best describes its functionality in general? Select all that apply. def foo(1st: list[int]): x - [) for iten in lst: if item X 2 1- 0: item 1 else: x.append(item) return x O foo returns a new list of elements containing only odd integers O foo returns a new list of elements containing only even integers O foo mutates list Ist, given a non-empty Ist O foo mutates list x, given a non-empty Ist O after foo executes, x and Ist contain the same elements (i.e., x- Ist) O foo has a syntax error O none of these options are correct
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- Write a function that gets a linked list of ints, and reverses it. For example - on input 1 -> 2 -> 3 -> 4, after the function finishes the execution, the list becomes 4 -> 3 -> 2 -> 1 - If the list has one element, then it doesn’t change - If the list is empty, then it doesn’t change You may use the data fields in the struct and the functions provided in LL.h and LL.c. // reverses a linked list void LL_reverse(LL_t* list); Test for the Function; void test_q3() { LL_t* lst = LLcreate(); LL_add_to_tail(lst, 1); LL_add_to_tail(lst, 3); LL_add_to_tail(lst, 8); LL_add_to_tail(lst, 4); LL_add_to_tail(lst, 3); LL_reverse(lst); intcorrect[] = {3,4,8,3,1}; inti; node_t* n = lst->head; for(i=0;i<5;i++) { if (n==NULL) { printf("Q3 ERROR: node %d==NULL unexpected\n", i); return; } if (n->data != correct[i]) { printf("Q3 ERROR: node%d->data==%d, expected %d\n", i, n->data, correct[i]); return; } n = n->next; } if (n==NULL) printf("Q3 ok\n"); } Support File…Implement the function below void swap(int pos1, int pos2) {} Inital code to be completed: class LinkedList : public List { node* head; node* tail; int index; node* create_node(int num) { node* n = (node*) malloc(sizeof(node)); n->element = num; n->next = NULL; return n; } public: LinkedList() { index = 0; head = NULL; tail = NULL; } int add(int num) { addTail(num); return index; } int get(int pos) { node* currnode = head; int count =0; while (currnode != NULL){ count++; if (count == pos){ return currnode -> element; }else{ currnode = currnode -> next; } } return -1; } int size() { return index; } void swap(int pos1, int pos2) { } // WARNING!…in javascript create a function that does the following and named as such, please dont copy the already answered question of this in the incorrect manner thank you!! grouper( xs, n ) This function takes a list of elements xs and an integer n. The function groups every n elements in xs as a list and returns a list of those groups. Each group in the resulting list will therefore be of length n, with the possible exception of the final group. The final group must be non-empty. Examples grouper( [1,2,3,4,5], 2 ) => [[1,2], [3,4], [5]] grouper( ['a','b','c','d','e'], 4 ) => [['a','b','c','d'],['e']] grouper( [], 3 ) => []
- Consider the following function:int enigma(NodeInt32* node){if(node == NULL)return 0; elsereturn 1 + enigma(node->next);} Which best describes the enigma function?A. The function performs a binary search of a list. B. The function computes the length of a list. C. The function sorts a list. D. None of the above.Please answer it in Python Write a function pairsbypairslist that would return pair by pair from the smallest value to the biggest value For example [12, 13, 11, 15], # return : (11, 12) and (13, 15) [9, 15, 4, 24, 19, 2] # return : (2,4) (9,15) (19,24) [1, 5, 9, 15, 21, 9, 12, 9], # return : (1,5) (9,9) (9,12) (15,21)write a function that add any item in a linked list after the item X, if the item X is not found in the linked list don't add the item. data structre please solve it fast less than 30 minute
- Please answer it in Python Write a function min_odd that takes a list as an argument and returns the smallest even integer contained in the list. If the list contains no even integers, the function will return None. For Example : min_odd([45, 62, 19, 22, 26, 18, 3, 5, 14])Expected answer is 14 min_odd([])Expected answer is None Write a function index_of that takes as an argument an integer (supposedly even) and a list, and returns the index to which this integer appears in the list. If the integer does not appear, the function will return None. It is assumed here for simplicity that the integer searched for does not appear several times in the list. Hint: if the for e in list loop doesn't suit you, remember that you can make a for + range or a while. .. For Example: index_of(34, [3, 67, 62, 34, 19, 24])Expected answer is 3 index_of(16, [2, 6, 104, 5, 25, 18, 50, 16])Expected answer is 7Write a function with the signature below that returns the sum of the last k elements of a singly linked list that contains integers. int returnSumOfLastKNodes(Node* head, int k) Example: 10 -> 5->8->15->11->9->23 10 represents the head node, returnSumOfLastKNodes(Node* head, 4) will return 58.Write a function piggyBank in Python that accepts a sequence of "coins" and returns counts of the coins and the total value of the bank. the coins will be given by a list of single characters, each one of 'Q','D','N',P', representing quarter, dime, nickel, penny the function returns a tuple with two items:1. a dictionary with counts of each denomination. They should always be listed in theorder 'Q','D','N',P'2. the total value in whole cents of the amount in the bank Sample result examples: >>> piggyBank(['D', 'P', 'Q', 'Q', 'D', 'P', 'P'])({'Q': 2, 'D': 2, 'N': 0, 'P': 3}, 73) >>> piggyBank(['D', 'D', 'N', 'N', 'N'])({'Q': 0, 'D': 2, 'N': 3, 'P': 0}, 35) >>> piggyBank(['P', 'D', 'N', 'P', 'N', 'N', 'N', 'Q', 'D', 'P', 'Q', 'Q', 'D'])({'Q': 3, 'D': 3, 'N': 4, 'P': 3}, 128) >>> piggyBank(['D', 'P', 'Q', 'Q', 'D', 'P', 'P'])==({'Q': 2, 'D': 2, 'N': 0,'P': 3}, 73)True Please only give to me the final code or "tool" that could generate any of the…
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