Consider the following function: int enigma(NodeInt32* node) { if(node == NULL) return 0; else return 1 + enigma(node->next); } Which best describes the enigma function? A. The function performs a binary search of a list. B. The function computes the length of a list. C. The function sorts a list. D. None of the above.

def reverse_list (1st: List [Any], start: int, end: int) -> None: """Reverse the order of the items in list , between the indexes and (including the item at the index). If start or end are out of the list bounds, then raise an IndexError. The function must be implemented **recursively**. >>> lst ['2', '2', 'v', 'e'] >>>reverse_list (lst, 0, 3) >>> lst ['e', 'v', 'i', '2'] >>> lst [] >>>reverse_list (lst, 0, 0) >>> lst [0] >>> Ist = [] >>> reverse_list (lst, 0, 1) Traceback (most recent call last): IndexError #1 #1

Suppose a node of a linked list is defined as follows in your program:    typedef struct{  int data;  struct Node* link;  } Node;    Write the definition of a function, printOdd(), which displays all the odd numbers of a linked list. What will be the time complexity of printOdd()? Express the time complexity in terms of Big-O notation.

Create a generic function print(ls, n) that prints to standard output the first n elements of list ls. The elements are printed on separate lines. If ls has less than n elements, then the entire list is printed.  I attached a picture of what I have so far. I'm having a hard time figuring out how I would make it print a certain number of elements that I specify.