Given the following String declaration: String phrase - "Ivan loves pancakes"; Fill in the blank with appropriate parameters to produce the following output: Pancakes?I lovecakes tring newwords = phrase.substring(. ) + phrase.substring(. phrase.substring(. stem.out.println("Pancakes? + newwords);

Given the following String declaration: String phrase - "Ivan loves pancakes"; Fill in the blank with appropriate parameters to produce the following output: Pancakes?I lovecakes tring newwords = phrase.substring(. ) + phrase.substring(. phrase.substring(. stem.out.println("Pancakes? + newwords);

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Why am I getting errors? Says "Index 0 out of bounds for length 0" public static void main(String[] args) { System.out.println("Enter length and width of rectangle"); for (int i=0; i < args.length; i++) { System.out.println(args[i]); } Double area= Double.parseDouble (args[0]) * Double.parseDouble (args[1]); System.out.println(" Area of rectangle is :" + String.format("%.3f", area)); } }
The files provided in the code editor to the right contain syntax and/or logic errors. In each case, determine and fix the problem, remove all syntax and coding errors, and run the program to ensure it works properly. public classDebugSeven3 { public static void main(String[] args) { String quote = "Honesty is the first chapter in the book of wisdom. - Thomas Jefferson"; System.out.println("index.of('f') is: " + quoteindexOf('f')); System.out.println("index.of('x') is: " + quoteindexOf('x')); System.out.println("char.At(5) is: " + quote.charAt(50)); System.out.println("endsWith(\"daughter\") is: " + quote.endsWith("daughter")); System.out.println("endsWith(\"son\") is: " + quote.endsWith("son")); System.out.println("replace('e', '*') is: ", quote.replace('e', '*')); }
screenchot of input and output import string pp = '''Peter Piper picked a peck of pickled peppers.A peck of pickled peppers Peter Piper picked.If Peter Piper picked a peck of pickled peppersWhere's the peck of pickled peppers Peter Piper picked?''' def remove_punc(s):'''Returns a copy of string s with all punctuation removed'''#This function is already written - don't change it!for char in string.punctuation:s = s.replace(char, '')return s def count_words(text):'''Returns a dictionary with words and their counts'''pass#Create an empty dictionary#Split the text into a list of words#For each word in the list#If the word is not in the dictionary#Add it with a count of 1#Otherwise#Add 1 to the count#Return the dictionary def show_counts(word_dict):'''Display words and their counts'''pass#Get a list of the keys from word_dict#Put the words in alphabetical order#For each word in the list#Print the word and its count def main():'''Controls the program'''text = remove_punc(pp.lower()) #text…
Write a program that takes a string as input and outputs the string in all capital letters and the length of the string. The output should follow the format from the example below. Example:Enter a DNA strand: aAtcDNA strand: AATCLength: 4Tip: make use of the .upper() method, the len() function, and the ‘\t’ escape character to add tabs.
I'm getting an error message where the FindText() is returning 0 instead of the proper amount of parameters. Here is the code #include <iostream> #include <string> using namespace std; char print_menu(string); int GetNumOfNonWSCharacters(string); int GetNumOfWords(string); void ReplaceExclamation(string&); void ShortenSpace(string&); int FindText(string, string); int main() { char opt; string tx, ph; cout << "Enter a sample text:\n\n"; getline(cin, tx); cout << "You entered: " << tx; do { opt = print_menu(tx); } while (opt == 'Q' || 'q'); // system("pause"); return 0; } char print_menu(string tx) { char ch1; string ph; cout << "\n\nMENU\n"; cout << "c - Number of non-whitespace characters\nw - Number of words\nf - Find text\nr - Replace all !'s\ns - Shorten spaces\nq - Quit"; cout << "\n\nChoose an option:\n"; cin >> ch1; switch (ch1) { case 'q': case 'Q': exit(0); case 'c': case 'C': cout << "\nNumber of…
Given string inputString on one line, character inputChar on a second line, and integer strIndex on a third line, output "Match found" if the character at index strIndex of inputString matches inputChar. Otherwise, output "Match not found". End with a newline. Ex: If the input is: warmth m 3 then the output is: Match found Note: Assume the length of string inputString is greater than strIndex. import java.util.Scanner; public class CharMatch {public static void main(String[] args) {Scanner scnr = new Scanner(System.in);String inputString; char inputChar; int strIndex; inputString = scnr.nextLine(); inputChar = scnr.next().charAt(0); strIndex = scnr.nextInt();/* Your code goes here */}}
Explain how the given program works. using System; class Program{ static void Main() { string text = "civic"; string reverse = ""; bool result; for(int x = text.Length - 1; x >= 0; x--){ reverse = reverse + text[x]; } result = text.Equals(reverse, StringComparison.CurrentCultureIgnoreCase) ? true:false; Console.WriteLine("Given text: {0}", text); Console.WriteLine("Reverse text: {0}", reverse); Console.WriteLine("Result: {0}", result); }}
Please solve the following problem by using the following code- #include <iostream>#include <string>using namespace std; class Instructor{private: string firstName; string lastName; string office; // Office Room Number e.g., N28A-L303 public: Instructor(string firstName, string lastName, string office) { this->firstName = firstName; this->lastName = lastName; this->office = office; } void print() const { cout << "First name: " << firstName << endl; cout << "Last name: " << lastName << endl; cout << "Office number: " << office << endl; }}; class TextBook{private: string title; // Book title string author; // Author name string publisher; // Publisher namepublic: TextBook(string title, string author, string publisher) { this->title = title; this->author = author; this->publisher = publisher;…
Code that need debugging fix with no errors // Gets a String from user // Converts the String to lowercase, and // displays the String's length // as well as a count of letters import java.util.*; public class DebugSeven4 { public static void main(String[] args) { Scanner kb = new Scanner(System.in); String aString ; int numLetters = 0; int stringLength; System.out.println("Enter a String. Include"); System.out.println("some uppercase letters, lowercase"); System.out.print("letters, and numbers >> "); aString = kb.nextLine(); stringLength = aString.length(); System.out.print("In all lowercase, the String is: "); for(int i = 0; i <= stringLength; i++) { char ch = Character.toLowerCase(aStringcharAt(i)); System.out.print(ch); if(!Character.isLetter(ch)) numLetters++; } System.out.println(); System.out.println ("The number of CHARACTERS…
The files provided in the code editor to the right contain syntax and/or logic errors. In each case, determine and fix the problem, remove all syntax and coding errors, and run the program to ensure it works properly // Makes String comparisonspublic class DebugSeven1{public static void main(String[] args){String name1 = "Roger";String name2 = "Roger";String name3 = "Stacy";if(name1.equals(name2))System.out.println(name1 + " and " + name2 +" are the same");if(name1.equals(name3))System.out.println(name1 + " and " + name2 +" are the same");if(name1.equals("roger));System.out.println(name1 + " and 'roger' are the same");if(name1.equals("Roger"));System.out.println(name1 + " and 'Roger' are the same");}}
PART G: COUNT HIGiven a string str, output the number of times the string “hi” appears anywhere in the string. Methods to use: substring(), length(), equals()Testing cases:abc hi ho => 1 ABChi hi => 2 hihi => 2 hiHIhi => 2 h => 0 hi => 1 Hi is no HI on ahI => 0 hiho not HOHIhi => 2
What is the output of the following code? { String myStr = new string("Cheggers2019"); System. out. print (myStr. substring(2, myStr . substring(0,2) . size( ) ) ) ; } } a. Error b. e c. No output d. eg