screenchot of input and output import stringpp = '''Peter Piper picked a peck of pickled peppers.A peck of pickled peppers Peter Piper picked.If Peter Piper picked a peck of pickled peppersWhere's the peck of pickled peppers Peter Piper picked?'''def remove_punc(s):'''Returns a copy of string s with all punctuation removed'''#This function is already written - don't change it!for char in string.punctuation:s = s.replace(char, '')return sdef count_words(text):'''Returns a dictionary with words and their counts'''pass#Create an empty dictionary#Split the text into a list of words#For each word in the list#If the word is not in the dictionary#Add it with a count of 1#Otherwise#Add 1 to the count#Return the dictionarydef show_counts(word_dict):'''Display words and their counts'''pass#Get a list of the keys from word_dict#Put the words in alphabetical order#For each word in the list#Print the word and its countdef main():'''Controls the program'''text = remove_punc(pp.lower()) #text is the name of the string with no punctuation#Use count_words to get a dictionary with words and counts#Use show_counts() to display words and countsmain() 2. Use a dictionary to count the number of occurrences of each word in some text and display thewords and their counts in alphabetical order. Make the text lower case (already done for you). Donot display any word that does not occur in the text. Use pp for the text - but your program shouldstill work if pp is changed.Save & RunLoad History1 import string23 pp = ''Peter Piper picked a peck of pickled peppers.4 A peck of pickled peppers Peter Piper picked.5 If Peter Piper picked a peck of pickled peppers6 Where's the peck of pickled peppers Peter Piper picked?'''78 def remove_punc (s) :'''Returns a copy of string s with all punctuation removed''"#This function is already written - don't change it!for char in string.punctuation:= = s.replace (char, '')10111213return s1415 def count_words (text) :16'''Returns a dictionary with words and their counts'''17pass18#Create an empty dictionary#Split the text into a list of words#For each word in the list192021#If the word is not in the dictionary22#Add it with a count of 123#Otherwise24#Add 1 to the count25#Return the dictionary 2627 def show_counts (word_dict) :28'''Display words and their counts'''29pass#Get a list of the keys from word dict3031#Put the words in alphabetical order32#For each word in the list33#Print the word and its count3435 def main ():36'''Controls the program'''text = remove_punc (pp.lower ()) #text is the name of the string#Use count_words to get a dictionary with words and counts#Use show_counts () to display words and counts3738394041 main ()42

Algorithm: Start Initialize a string Remove punctuation from the string Split the string and find…

Answered: screenchot of input and output…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

screenchot of input and output

import string

pp = '''Peter Piper picked a peck of pickled peppers.
A peck of pickled peppers Peter Piper picked.
If Peter Piper picked a peck of pickled peppers
Where's the peck of pickled peppers Peter Piper picked?'''

def remove_punc(s):
'''Returns a copy of string s with all punctuation removed'''
#This function is already written - don't change it!
for char in string.punctuation:
s = s.replace(char, '')
return s

def count_words(text):
'''Returns a dictionary with words and their counts'''
pass
#Create an empty dictionary
#Split the text into a list of words
#For each word in the list
#If the word is not in the dictionary
#Add it with a count of 1
#Otherwise
#Add 1 to the count
#Return the dictionary

def show_counts(word_dict):
'''Display words and their counts'''
pass
#Get a list of the keys from word_dict
#Put the words in alphabetical order
#For each word in the list
#Print the word and its count

def main():
'''Controls the program'''
text = remove_punc(pp.lower()) #text is the name of the string with no punctuation
#Use count_words to get a dictionary with words and counts
#Use show_counts() to display words and counts

main()

2. Use a dictionary to count the number of occurrences of each word in some text and display the
words and their counts in alphabetical order. Make the text lower case (already done for you). Do
not display any word that does not occur in the text. Use pp for the text - but your program should
still work if pp is changed.
Save & Run
Load History
1 import string
2
3 pp = ''Peter Piper picked a peck of pickled peppers.
4 A peck of pickled peppers Peter Piper picked.
5 If Peter Piper picked a peck of pickled peppers
6 Where's the peck of pickled peppers Peter Piper picked?'''
7
8 def remove_punc (s) :
'''Returns a copy of string s with all punctuation removed''"
#This function is already written - don't change it!
for char in string.punctuation:
= = s.replace (char, '')
10
11
12
13
return s
14
15 def count_words (text) :
16
'''Returns a dictionary with words and their counts'''
17
pass
18
#Create an empty dictionary
#Split the text into a list of words
#For each word in the list
19
20
21
#If the word is not in the dictionary
22
#Add it with a count of 1
23
#Otherwise
24
#Add 1 to the count
25
#Return the dictionary

26
27 def show_counts (word_dict) :
28
'''Display words and their counts'''
29
pass
#Get a list of the keys from word dict
30
31
#Put the words in alphabetical order
32
#For each word in the list
33
#Print the word and its count
34
35 def main ():
36
'''Controls the program'''
text = remove_punc (pp.lower ()) #text is the name of the string
#Use count_words to get a dictionary with words and counts
#Use show_counts () to display words and counts
37
38
39
40
41 main ()
42

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