Given the following time-cɔmplexity functions, fiE O(Wn) f2 E O(n) which algorithm is faster for large inputs? O a. Algorithm one is faster. b. Algorithm two is faster. c. The two algorithms are equally fast. d. We can not tell from the information given.
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- Use the Runge-Kutta Fehlberg Algorithm to approximate the solution to the following initial-value problems. This is a numerical analysis problemAn account on server A is more expensive than an account on server B. However, server A is faster. To see if it’soptimal to go with the faster but more expensive server, a manager needs to know how much faster it is. A certaincomputer algorithm is executed 30 times on server A and 20 times on server B with the following results:T-Value = -3.12 P-Value = 0.002 DF = 48Is server A really faster? How strong is the evidence? Formulate the suitable hypothesis and alternative and conclude at5% level of significance.In Example 7.5, we implied that each of the five observations was from one period of time, such as a particular week. Suppose instead that each isan average over several weeks. For example, the 4.7 million exposures corresponding to one ad might really be an average over 15 different weeks where one ad was shown in each of these weeks. Similarly, the 90.3 million exposures corresponding to 50 ads might really be an average over only three different weeks where 50 ads were shown in each of these weeks. If the observations are really averages over different numbers of weeks, then simply summing the squared prediction errors doesn’tseem appropriate. For example, it seems more appropriate that an average over 15 weeks should get five times as much weight as an average over only three weeks. Assume the five observations inthe example are really averages over 15 weeks, 10 weeks, 4 weeks, 3 weeks, and 1 week, respectively. Devise an appropriate fitting function, to replace sum of squared…
- 1.9 A local television station plans to drop three Friday evening programs at the end of the season. Steve Botuchis, the station manager, developed a list of three potential replacement programs. Estimates of the advertising revenue (in dollars) that can be expected for each of the new programs in the three vacated time slots are as in Table 3. Mr. Botuchis asked you to find the assignment of programs to time slots that will maximize total advertising revenue.question 2 Hiring workers A company payshis skilled workers S15 per hour in his departmentassembly tool. semi-skilled workersin that department they earn S9 per hour To the employeestwo of shipments are paid SIO per hour Because of aincrease in orders, the company needs to contractemploy a total of 70 workers in the departments ofassembly and shipping Will pay a total of $760 per hourto these employees. Because of a contract with the unionlaw, twice as many semi-semi-workers should be employed.lified than skilled workers. How manysemi-skilled workers, skilled workers and employees ofshipments should hire the company? Note: Solve by Inverse-Excel # OF SEMI-SKILLED WORKERS # OF SKILLED WORKERS # OF SHIPPING WORKERSWhich of the following is the largest number of jobs that could theoretically be within the software industry at present, based on the information available? A) 1,4 million B) 2,4 million C) 4 million D) 8 million E) 10 million Transcribed Image Text:Preparing for Automation The possibility of having robots or mechanical assistants completing our laborious, dangerous, or repetitive day-to-day tasks has long been a dream of humanity. Now, as Robotic Process Automation (RPA) becomes commonplace, this dream or concern, depending on viewpoint - is getting closer. RPA, far from the walking, talking android commonly found in science fiction series, can be thought of as a programmable piece of software which, through using a series of rules, will complete repetitive tasks with a lower error rate and less interruption than a human completing the same tasks. The aim of RPA, beyond improving efficiency, is to free up humans from the monotony of roles like data entry, stock management and…
- Question 3B CWD Electronics sells Televisions (TV), which it orders from the USA. Because of shipping and handling costs, each order must be for 10 TVs. Because of the time it takes to receive an order, the company places an order every time the present stock drops to 5 TVs. It costs $50 to place anorder. It costs the company $200 in lost sales when a customer asks for a TV and the warehouse is out of stock. It costs $50 to keep each TV stored in the warehouse. If a customer cannot purchase a TV when it is requested, the customer will not wait until one comes in but will go to a competitor.The following probability distribution for demand for TV has been and the time required to receive an order once it is placed (lead time) has the following probability distribution: The company has 10 TVs in stock. Orders are always received at the beginning of the week. Note that a lead time of 2 weeks imply that an order placed in week one will arrive in week 4. Hint . No order is placed until…An advantage of different emergence patterns for two species of a swarming insect is that they rarely emerge the same year to compete for food. Suppose that type A of the insect has a 5-year emergence cycle and type B of the insect has a 19-year cycle. If both species of the insect emerged during 2011 , when is the next year that both species will emerge during the same year?28-29 fast please Questions 28-29 refer to the following: A hypothesis is conducted to see if a new algorithm is faster than an old one. Eight problems are solved twice, the first time using the old algorithm and the second time using the new algorithm. Of interest is the average decrease in time. The difference data ( old-new ) is calculated Program Old (time in seconds) New (time in seconds) Difference ( old - new) 1 8.05 6.3 1.75 2 24.74 12.1 12.64 3 28.33 19.5 8.83 4 8.45 5.63 2.82 5 9.19 10.21 -1.02 6 25.2 25.4 -0.2 7 14.05 10.2 3.85 8 20.33 14.63 5.70 The distribution of the test is: Group of answer choices Normal student-t with df 8 student-t with df 7 Unable to determine The conclusion to the test is Group of answer choices The new algorithm is not faster than the old one The new algorithm is the same as the old one The new algorithm is…
- The owner of a pet store is trying to decide whether to discontinue selling specialty clothes for pets. She suspects that only 10% of the customers buy specialty clothes for their pets and thinks that she might be able to replace the clothes with more interesting and profitable items on the shelves. Before making a final decision she decides to keep track of the total number of customers for a day, and whether they purchase specialty clothes for their pet. a) Assuming the pet store owner is correct in thinking that only 10% of her customers purchase specialty clothes for their pets, how many customers should she expect before someone buys a garment for their pet? b) What is the probability that she does not sell a garment until the 5th customer? c) What is the probability that exactly 4 of the first 10 customers buy specialty clothes for their pet? d) What is the probability that at least 3 of the first 35 customers buy specialty clothes for their pet?…Q2. Suppose you have been appointed the County Executive in charge of finance in your County. You have allocated funding to two projects, Project A and Project B. By coincidence, Project B happens to be located in your Sub- County. Given below are seventy allocations to various activities in both projects (in Kshs Billions). Funding for Project A 96 21 80 38 20 60 21 50 100 15 81 06 55 40 70 70 10 30 30 35 66 53 50 60 80 35 80 55 50 49 51 60 25 90 90 50 95 50 80 65 60 55 20 30 110 65 50 65 60 80 64 50 66 35 40 60 65 50 51 81 36 90 51 80 50 55 80 30 60 96 Funding for Project B 20 66 59 21 101 108 31 65 34 20 35 80 63 36 95 89 61 48 44 25 50 81 68 59 50 15 21 29 54 50 45 55 80 65 40 29 81 20 104 65 51 60 10 45 60 35 96 55 24…In his doctoral thesis, L. A. Beckel (University of Minnesota, 1982) studied the social behavior of river otters during the mating season. An important role in the bonding process of river otters is very short periods of social grooming. After extensive observations, Dr. Beckel found that one group of river otters under study had a frequency of initiating grooming of approximately 1.7 for each 10 minutes. Suppose that you are observing river otters for 40 minutes. Let r = 0, 1, 2, ... be a random variable that represents the number of times (in a 40-minute interval) one otter initiates social grooming of another. Lambda = 6.8 (b) Find the probabilities that in your 40 minutes of observation, one otter will initiate social grooming four times, five times, and six times. (Round your answers to four decimal places.) P(4) = P(5) = P(6) =