Given the function g(x) = 4x° + 30x2 + 48x, find the first derivative, g'(x). gʻ(x) = Notice that g'(x) O when x = - 1, that is, %3D g'( – 1) = 0. Now, we want to know whether there is a local minimum or - 1, so we will use the second local maximum at x = derivative test. Find the second derivative, g''(x). = (x),,6 Evaluate g''( - 1). g''(– 1) = Based on the sign of this number, does this mean the graph of g(x) is concave up or concave down at a = [Answer either up or down -- watch your spelling!!] - 1 the graph of g(x) is concave 1? At x = Based on the concavity of g(x) at x = mean that there is a local minimum or local maximum at 1, does this x = 1? [Answer either minimum or maximum -- watch your spelling!!] At x = – 1 there is a local

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Given the function g(x) = 4x + 30x + 48x, find the
first derivative, g'(x).
g'(x) =
Notice that g'(x) =
O when x =
- 1, that is,
g'( – 1) = 0.
Now, we want to know whether there is a local minimum or
– 1, so we will use the second
local maximum at x =
derivative test.
Find the second derivative, g''(x).
g''(x)
Evaluate g''( - 1).
g''( – 1) =
Based on the sign of this number, does this mean the graph
- 1?
watch your spelling!!]
of g(x) is concave up or concave down at x =
[Answer either up or down
At x
1 the graph of g(x) is concave
Based on the concavity of g(x) at x =
mean that there is a local minimum or local maximum at
- 1, does this
r = -
1?
watch your
[Answer either minimum or maximum
spelling!!]
--
At x =
1 there is a local
Transcribed Image Text:Given the function g(x) = 4x + 30x + 48x, find the first derivative, g'(x). g'(x) = Notice that g'(x) = O when x = - 1, that is, g'( – 1) = 0. Now, we want to know whether there is a local minimum or – 1, so we will use the second local maximum at x = derivative test. Find the second derivative, g''(x). g''(x) Evaluate g''( - 1). g''( – 1) = Based on the sign of this number, does this mean the graph - 1? watch your spelling!!] of g(x) is concave up or concave down at x = [Answer either up or down At x 1 the graph of g(x) is concave Based on the concavity of g(x) at x = mean that there is a local minimum or local maximum at - 1, does this r = - 1? watch your [Answer either minimum or maximum spelling!!] -- At x = 1 there is a local
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