Given the thermochemical equations   X2+3Y2⟶2XY3Δ?1=−380    X2+2Z2⟶2XZ2Δ?2=−130 kJ     2Y2+Z2⟶2Y2ZΔ?3=−290 kJ   Calculate the change in enthalpy for the reaction.   4XY3+7Z2⟶6Y2Z+4XZ2

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