Given two arrays A and B of equal size N, the task is to find if given arrays are equal or not. Two arrays are said to be equal if both of them contain same set of elements, arrangements (or permutation) of elements may be different though. Note : If there are repetitions, then counts of repeated elements must also be same for two array to be equal. Example 1: Input: N = 5 A[] = {1,2,5,4,0} B[] = {2,4,5,0,1} Output: 1.
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Given two arrays A and B of equal size N, the task is to find if given arrays are equal or not. Two arrays are said to be equal if both of them contain same set of elements, arrangements (or permutation) of elements may be different though.
Note : If there are repetitions, then counts of repeated elements must also be same for two array to be equal.
Example 1:
Input: N = 5 A[] = {1,2,5,4,0} B[] = {2,4,5,0,1} Output: 1.
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- Given an array A[0 : n−1] of n integers, compute the maximum sum of non-empty consecutive subsequence present in the array. For example, if the input is A = [3, 2, 5, 1, 6], then the output max sum is 17 (the corresponding maximum sum consecutive subsequence is [3, 2, 5, 1, 6]. If the input is A = [−2, 11, −4, 13, −5, −2], then the output max sum is 20 (the corresponding maximum sum consecutive subsequence is [11, −4, 13]. (a) Given input A[0 : n − 1] and n, design a divide-and-conquer algorithm which outputs the maximum sum of non-empty consecutive subsequence in the array. You only need to output the sum value and do not need to output the exact subsequence. [We are expecting a brief justification for the intuitive idea of the algorithm and the pseudocode of the algorithm.] (b) Let T(n) be the runtime of your algorithm when the input size is n. Establish the recurrence relation of T(n) for the algorithm, and then solve the recurrence relation to provide the big-O runtime of the…Given an array A[0 : n−1] of n integers, compute the maximum sum of non-empty consecutive subsequence present in the array.For example, if the input is A = [3, 2, 5, 1, 6], then the output max sum is 17 (the corresponding maximum sum consecutive subsequence is [3, 2, 5, 1, 6]. If the input is A = [−2, 11, −4, 13, −5, −2], then the output max sum is 20 (the corresponding maximum sum consecutive subsequence is [11, −4, 13].(a) Given input A[0 : n − 1] and n, design a divide-and-conquer algorithm which outputs the maximum sum of non-empty consecutive subsequence in the array. You only need to output the sum value and do not need to output the exact subsequence. [We are expecting a brief justification for the intuitive idea of the algorithm and the pseudocode of the algorithm.](b) Let T(n) be the runtime of your algorithm when the input size is n. Establish the recurrence relation of T(n) for your algorithm, and then solve the recurrence relation to provide the big-O runtime of your…Let A and B be two arrays of length n, each containing a random permutation of the numbers from 1 to n. An inversion between the two permutations A and B is a pair of values (x, y) where the index of x is less than the index of y in array A, but the index of x is more than the index of y in array B. Design an algorithm which counts the total number of inversions between A and B that runs in O(n log n) time.
- Given an array, find the total number of inversions of it. If (i < j) and (A[i] > A[j]), then pair (i, j) is called an inversion of an array A. We need to count all such pairs in the array. For example, Input: A[] = [1, 9, 6, 4, 5] Output: The inversion count is 5 There are 5 inversions in the array: (9, 6), (9, 4), (9, 5), (6, 4), (6, 5)Given an array of intervals where intervals[i] = [starti, endi], merge all overlapping intervals, and return an array of the non-overlapping intervals that cover all the intervals in the input. Example 1: Input: intervals = [[1,3],[2,6],[8,10],[15,18]] Output: [[1,6],[8,10],[15,18]] Explanation: Since intervals [1,3] and [2,6] overlap, merge them into [1,6]. Example 2: Input: intervals = [[1,4],[4,5]] Output: [[1,5]] Explanation: Intervals [1,4] and [4,5] are considered overlapping. Solve it in Java Language pleaseYou have an array of 10,000 subject scores for a high-school exam and you want to find the scores that are ranked from 4900 to 5100 that is the 201 most middle-ranked scores. Precisely describe two alternative algorithmic ap proaches to doing this - one of which is, in terms of time complexity, more efficient than the other.
- Given an integer n and an array a of length n, your task is to apply the following mutation to a: Array a mutates into a new array b of length n. For each i from 0 to n - 1, b[i] = a[i - 1] + a[i] + a[i + 1]. If some element in the sum a[i - 1] + a[i] + a[i + 1] does not exist, it should be set to 0. For example, b[0] should be equal to 0 + a[0] + a[1].Implement the vacuum cleaning agent function in Python/Java for the scenario described below: Consider two-dimensional Boolean array of size m x n (m and n can each be equal to 4) where m is the number of rows, and n is the number of columns. Obtain numerical positive integer values for m and n as inputs from the user. Generate random numbers and scale them down to either a “0” or a “1” according to whether they represent “Clean” or “Dirty”, respectively. After filling the array with 0s or 1s, start at some random array position indicating the initial position of the vacuum cleaner. First check if at that current position, there is the presence of a “Dirt” or not determined by whether 0 or 1 is filled in at that initial position of the vacuum cleaner. If there is a “Dirt”, clean it, and if there is no “Dirt” do a No-operation. After this is done, generate random numbers modulo 4 to obtain random numbers 0, 1, 2, 3 indicating whether to take a left, right, up or down correspondingly. If…(Write the code in java)Given 2 sorted arrays (in increasing order), find a path through the intersection that produces the maximum sum and return the maximum sum. That is, we can switch from one array to another array only at common elements. If no intersection element is present, we need to take the sum of all elements from the array with greater sum. Sample Input: 6 1 5 10 15 20 25 5 2 4 5 9 15 Sample Output : 81 Explanation : We start from array 2 and take sum till 5 (sum = 11). Then we'll switch to array at element 10 and take till 15. So sum = 36. Now, no elements are left in array after 15, so we'll continue in array 1. Hence the sum is 81.
- Write a program that reads a list of integers from input into an array and outputs "yes" if the list is sorted in ascending order between two provided positions. Otherwise, output "no". The first input specifies the number of items in the list. The next set of inputs is the list. The last two inputs are the start and end positions (inclusive). Assume the list contains less than 20 integers and position 1 is the first element. Ex: If the input is: 8 5 6 7 4 3 2 1 0 1 3 the output is: yes Ex: If the input is: 6 1 2 3 4 5 2 4 6 the output is: noConsider an array A of N values (N entered by the user). Write a C program that creates a second array B such that the i-th element of B, i.e., B[i] is equal to A[0] *A[1] * A[2] * ... A[i]; In other words:- B[0] = A[0]- B[1] = A[0] * A[1];- B[2] = A[0] * A[1] * A[2];- B[3] = A[0] * A[1] * A[2] * A[3]- ....etc.For this exercise, we would like to implement two solutions and compare their complexity /performance in terms of computation time.Solution 1: Implement blindly the following algorithms: for each element B[i], compute A[0] *A[1] * A[2] * .... *A[i] and save the result in B[i];To test the solution, create an array A of 1000 elements and initialize each of its elements with arandom value (instead of asking the user to . To do that, use the function rand, which, every timecalled, returns a random number Questions:- How long does your program take to produce the solution?- Analyze the solution above and explain why it is taking long time. What are the mainfactors that affect how long…Write a program that reads an array A of N elements containing only 0's and 1's. Your program should find the position of a 0 and replace it with a 1 to get the longest continuous sequence of 1's. Let this position of 0 be called P. Print P if such a 0 exists and print -1 if the original array A contains only 1's. Assume the array indexing starts from 0.