Gold has the Face-Centered Cubic (FCC) crystal structure shown in the figure below. The atomic radius of Gold is r = 0.1442 nm at room temperature (20°C). Calculate the edge length "a" of the unit cell

Gold has the Face-Centered Cubic (FCC) crystal structure shown in the figure below. The atomic radius of Gold is r = 0.1442 nm at room temperature (20°C). Calculate the edge length "a" of the unit cell

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Related questions

Q: With the information on its molar volume and lattice parameter, a, determine the crystal structure…

A: Given: Vmol - 5.9 cm3/mol Lattice parameter : 2.15 A To find : structure of the crystal

Q: 10. Lithium crystallizes in a bcc structure with an edge length of 3.509 Å. Calculate its density.…

Q: A hypothetical metal has the SC crystal structure, a density of 7.08 g/cm3, and an atomic weight of…

Q: 8. In an ideal hexagonal closed packed system, if the atomic radius of the atom was 0.254 nm, write…

A: Given data, The given lattice is hexagonal closed packed(HCP). r = Radius of the atom = 0.254 nm To…

Q: Scandium (Sc) has the Face-Centered Cubic (FCC) crystal structure. The edge length is a = 0.452 nm.…

Q: Draw the following crystal directions within an orthorhombic unit cell: [101], [112], [100], [110],…

A: The above question is based on orthorombic unit cell.

Q: What are the types of 0-D lattice imperfections found in crystals? Which defect will contribute to…

Q: Silver crystallizes as fcc structure. If the density of silver is 10.51g/cm3. Calculate the volume…

Q: Select the correct indices for the planes and directions in the cubic unit cell shown in Figure…

Q: According to the hard-sphere model, illustrate with draw figure the contributions of atoms in the…

Q: Q 5: In the cubic cell unit find: A- Miller's indices of the directions shown in Figure (4) B-…

A: Miller indices: It is a set of three number which shows the orientation of a set of parallel planes…

Q: Vanadium has the Body-Centered Cubic (BCC) crystal structure shown in the figure below. The radius…

A: Given bcc vanadium r=0.132nm

Q: 8- Tungsten W (atomic weight = 183.84 g/mol) forms a body centered cubic (bcc) unit cell. If…

A: For the BCC structure the length of the side is a3=4ra=4×atomic radius3=4×1473=339.5 Pm×10-121…

Q: In the' simple cubic crystal lattice'structure, specify the 'Atomic fill factor' and the 'Planar…

A: Simple cubic crystal eight atoms at the eight cornors of the cubeLattice parameter or side length of…

Q: 1. Aluminum has a FCC structure. If the atomic radius of aluminum is 0.143 nm, calculate the volume…

A: We are suppose to solve only one question. Please post other question as a separate question.

Q: Rhodium (Rh) has the Face-Centered Cubic (FCC) crystal structure. The atomic radius of Rhodium is r…

A: Ans-a(0.379nm)

Q: Vanadium has the Body-Centered Cubic (BCC) crystal structure. The edge length "a" of the unit cell…

Q: 8- Tungsten W (atomic weight = 183.84 g/mol) forms a body centered cubic (bcc) unit cell. If…

Q: Platinum is a metal having a FCC crystal structure with a density p= 21.45 kg/m3. Calculate the…

Q: Polonium is an element with a simple cubic crystal arrangement. Find the radius of the polonium…

Q: edge

A: The edge length of FCC structure can bd calculated By using relationship a=4*r/√2

Q: metal is found to have BCC structure, a lattice constant of 3.31 Å, and a density of 16.6 g/cm3 .…

A: Density=Z×Atomic weight of metalNA×Volume of unit cell For BCC Z=2n NA=Avagadros Number Volume =a3…

Q: Calculate the volume of an FCC(Face Center Cubic) unit cell (cell edge length a) in terms of the…

A: It is required to determine volume of FCC Unit cell

Q: Europium has the Body-Centered Cubic (BC) crystal structure shown in the figure below. The radius of…

A: Ans-C

Q: 3. the iron has crystal lattice type (BCC) at (910°c) degrees Celsius and becomes (FCC) above this…

A: We know that the packing efficiency of BCC structure is 68%,that means the space occupied by the…

Q: Gold has the Face-Centered Cubic (FCC) crystal structure shown in the figure below. The atomic…

Q: 1) The density of a metal, which has the BCC structure and one atom per lattice point, is 0.855…

A: given data: density of metal in bcc structure=0.855g/cm3 atomic weight =39.09g/mol

Q: Iron exhibits an allotropic behavior change of solid state structure in such a way that when it is…

Q: Q 7(a): Derive planar density expressions for FCC (100) and (111) planes in terms of the atomic…

Q: Calculate the atomic densities of the directions [100], [111] and [110] in a face centered cubic…

Q: Given that molybdenum (Mo) with atomic weight 95.94 g/mol and density 10.2 g/cm3 assumes a…

Q: If the atomic radius of a metal that has the facecentered cubic crystal is 0.137 nm , calculate the…

Q: Compare the (100) and the (200) FCC crystallographic planes. Are they the same? Compare the (111)…

A: GivenPlanes 1,0,0 (2,0,0)planes (1,1,1) (2,2,2)

Q: Calcium has the Face-Centered Cubic (FCC) crystal structure shown in the figure below. The atomic…

A: Given Data: FCC crystal Structure The atomic radius of calcium r=0.197 nm at room temperature 20°C…

Q: 17- In a given FCC crystal unit cell with a lattice constant "a", calculate the planer density of…

Q: Draw the [1 1 0], [-1 1 0], [ 0 -1 -1] directions for FCC and prove they are crystallographically…

A: [ 1 1 0 ] => Miller Indices

Q: Aluminum metal was determined to have an atomic weight of 26.9815 g/mol and an atomic radius of…

Q: Iron (Fe) has the Body-Centered Cubic (BCC) crystal structure. The edge length is a = 0.2864 nm.…

A: Answer: The linear density in (atmos/nm) along direction [0 1 1] is 2.47 atmos/nm.

Q: In an ideal hexagonal closed packed system, if the atomic radius of the atom was 0.112 nm, write…

Q: If the atomic radius of a metal that has the face centered cubic crystal is 0.137 nm , calculate the…

Q: A hypothetical tetrahedral crystal has the following lattice parameters: a = b = 0.40 nm, c = 0.5…

A: Given details: a=b=0.4 nmc=0.5 nmα=β=γ=90°

Q: Calcium has the Face-Centered Cubic (FCC) crystal structure shown in the figure below. The atomic…

A: Given: Atomic radius of calcium,r=0.197 nm Consider the Cubic structure for FCC: According to the…

Q: Silver (Ag) has the Face-Centered Cubic (FCC) crystal structure shown in the figure below. The…

A: Given : Radius of atom ( silver ) =0.144nm Given crystal is FCC crystal We have to calculate…

Q: Determine the indices for the directions shown for A, B, C and D in the cubic unit cell in Figure…

Q: In Fig. 3.2, must it be true that the dislocation segments at points C and C' are screw…

A: Dislocation- Dislocation is a linear crystallographic defect that contains an uneven change in the…

Q: uestion Six: For an FCC crystal: calculate the density of atoms (atoms/a where a is the lattice…

A: here the radius of the atom is given a For the FCC crystal structure, the planar density for the…

Q: Iron (Fe) has the Body-Centered Cubic (BCC) crystal structure shown in the figure below. The radius…

Q: Europium has the Body-Centered Cubic (BCC) crystal structure shown in the figure below. The radius…

Q: (d) Solve the linear densities of the direction [100] and [110] on aluminium which has a face…

Q: Determine the indices for the directions in the cubic unit cell shown in below Figure 3 4 C D A B)

Concept explainers

The Space Lattice and Unit Cells

Every matter consists of atoms, molecules, and ions. If these atoms, molecules, and ions (micro-particles) are represented in a three-dimensional space-occupying certain specific points in space, then these arrangements are termed as space lattices and the specific points which are being occupied by atoms, molecules and ions are termed as lattice points. The atoms, molecules, and ions at the lattice points are generally grouped in a regular fashion and repeat periodically at the three-dimensional space.

Question

0: (34 || 4 10:14
Gold has the Face-Centered Cubic
(FCC) crystal structure shown in the
figure below. The atomic radius of
Gold is r = 0.1442 nm at room
temperature (20°C).
Calculate the edge length “a" of the
unit cell
Select one:
a. 0.333
b. 0.408
c. 0.488
d. 0.612
e. None of these

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Principal Metallic Crystal Structures and Crystal Structure Analysis

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Similar questions

Derive the dimension ratio c/a for regular HCP crystal. Please do not use the atomic packing factor
Derive the dimension ratio c/a for regular HCP crystal. Note: Please do not use the atomic packing factor in the derivation.
1- The density of the elemental magnesium crystal structure, which is in the face centered cubic structure, is 1,738 g / cm3. Specify the side lengths of the crystal lattice. 2-Polonium is an element with a simple cubic crystal arrangement. Find the radius of the polonium atoms in this structure with a density of 9.4 g / cm3 and a weight of 209 g / atom. 3- A wire with a diameter of 9.6 mm is pulled with a force of 18,000 N. With this loading, the initial length of the wire that grows 1.5 mm is 400 mm. Find the engineering voltage.
The attached photo shows the Young’s modulus of a cubic single crystal as a function of orientation. where a1 a2 and a3 are the direction cosines between the direction hkl and [100], [010], and [001], respectively. For a certain crystal, E111 = 500 GPa and E100 = 90 GPa. Calculate Young’s modulus for this single crystal in the <110> direction
A paper clip has a mass of 10.75 grams and is made of gold. (FCC, R = 0.1442 nm), calculate: a) The number of unit cells in the sample volume. b) The number of atoms contained in the volume of the sample.
Determine the indices for the following crystallographic direction. Must show complete solution following the steps below, and use proper notation. Steps in defining the 3 directional indices 1. Vector repositioning (if necessary) to pass through origin. (needed in this case) 2. Read off projections in terms of unit cell dimensions a, b, and c 3. Adjust to smallest integer values 4. Enclose in square brackets, no commas → [u v w]
A single crystal Al,O, rod (precisely 6 mm diameter7 60 mm long) is used to apply loads to smalsamples in a high-precision dilatometer (a longin.measuring device). Calculate the resulting imdimensions if the crystal is subjected to a 33-kN arigcompression load.
The spacing between two adjacent (123) planes in a simple cubic crystal with the lattice parameter a=0.4 nm is _______ (nm). Draw [322] in a body centered cubic crystal. Draw (202) in a face centered cubic crystal. The planar density of (003) should be higher than that of (002) in a body centered cubic crystal. Ture___ or False____. You need to justify why to the answer.
With a hexagonal crystal structure where a0=0.22858nm, co=0.35842nm, an atomic radius of 0.1143nm, density of 1.848g/cm3, and an atomic weight of 9.01g/mol, what is a)number of atoms in each unit cell and b) the packing factor in each unit cell.
Copper has an atomic radius of 0.128 nm, an FCC crystal structure, and an atomic weight of 63.5 (a.m.u). Compute its theoretical density. Also , compute the theoretical density if the crystal structure is BCC.
How many vacancies per cubic centimeter are there in gold, at ambienttemperature, assuming a lattice parameter of 0.408 nm? Gv = 1.4 × 10−19.
Compute the density of Zinc, where the atomic radius of Zn=1.453×10-8 and atomic weight =72.4 g/mol and the crystal structure is BCC?