Grandpa stills plays his old 78's on an antique Victrola. If the records are 10.0 inches in diameter and the 78 refers to the number of revolutions per minute, what is the centripetal acceleration (in m/s?) of a dust particle on the edge of a rotating record? (Hint: 1 revolution = 1 cycle = 1 circumference of travel) Use: 1.00 inch = 2.54 cm (exact)

Grandpa stills plays his old 78's on an antique Victrola. If the records are 10.0 inches in diameter and the 78 refers to the number of revolutions per minute, what is the centripetal acceleration (in m/s?) of a dust particle on the edge of a rotating record? (Hint: 1 revolution = 1 cycle = 1 circumference of travel) Use: 1.00 inch = 2.54 cm (exact)

College Physics

10th Edition

ISBN:9781285737027

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter7: Rotational Motion And The Law Of Gravity

Section: Chapter Questions

Problem 8WUE: A car of mass 1 230 kg travels along a circular road of radius 60.0 m at 18.0 m/s. (a) Calculate the...

See similar textbooks

Similar questions

A door in a hospital has a pneumatic closer that pulls the door shut such that the doorknob moves with constant speed over most of its path. In this part of its motion, (a) does the doorknob experience a centripetal acceleration? (b) Does it experience a tangential acceleration?
An ordinary workshop grindstone has a radius of 7.50 cm and rotates at 6500 rev/min. (a) Calculate the magnitude of the centripetal acceleration at its edge in meters per second squared and convert it to multiples of g.
Which of the following is impossible for a car moving in a circular path? Assume that the car is never at rest. (a) The car has tangential acceleration but no centripetal acceleration. (b) The car has centripetal acceleration but no tangential acceleration. (c) The car has both centripetal acceleration and tangential acceleration.
A runner taking part in the 200 m dash must run around the end of a track that has a circular arc with a radius of curvature of 30 m. If he completes the 200 m dash in 23.2 s and runs at constant speed throughout the race, what is the magnitude of his centripetal acceleration as he runs the curved portion of the track?
A point on a rotating turntable 20.0 cm from the center accelerates from rest to a final speed of 0.700 m/s in 1.75 s. At t = 1.25 s, find the magnitude and direction of (a) the radial acceleration, (b) the tangential acceleration, and (c) the total acceleration of the point.
Explain why centripetal acceleration changes the direction of velocity in circular motion but not its magnitude.
A merry-go-round is stationary. A clog is running around the merry-go-round on the ground just outside its circumference, moving with a constant angular speed of 0.750 rad/s. The dog does not change his pace when he sees what he has been looking for: a bone resting on the edge of the merry-go-round one- third of a revolution in front of him. At the instant the dog sees the bone (t = 0), the merry-go-round begins to move in the direction the dog is running, with a constant angular acceleration of 0.015 0 rad/s2. (a) At what time will the dog first reach the bone? (b) The confused dog keeps running and passes the bone. How long after the merry-go-round starts to turn do the dog and the bone draw even with each other for the second time?
The Moon's mass is 7.35 1022 kg, and it moves in a nearly circular orbit with radius 3.84 108 m. The period of its motion is 27.3 days. Use this, information to determine the Moon's (a) orbital speed and (b) its acceleration.
What is the average speed in mi/h of a person at the equator as a result of the Earths rotation? (Take the radius of the Earth to be RE = 4000 mi.)
A car of mass 1 230 kg travels along a circular road of radius 60.0 m at 18.0 m/s. (a) Calculate the magnitude of the cars centripetal acceleration. (b) What is the magnitude of the force of static friction acting on the car? (See Section 7.4.)
The following objects are moving in uniform circular motion. Draw a free-body diagram for each object and identify the force responsible for the centripetal acceleration. Object 1. A person riding on the barrel-of-fun ride (Fig. 6.27, top) Object 2. The lead object in the laboratory set-up (Fig. 6.27, center) Object 3. A jogger running on a circular track (Fig. 6.27, bottom)
An athlete swings a ball, connected to the end of a chain, in a horizontal circle. The athlete is able to rotate the ball at the rate of 8.00 rev/s when the length of the chain is 6.600 m. When be increases the length to 0.900 m, he is able to rotate the ball only 6.00 rev/s. (a) Which rate of rotation gives the greater speed for the ball? (b) What is the centripetal acceleration of the ball at 8.00 rev/s? (c) What is the centripetal acceleration at 6.00 rev/s?