graph the parabola. determine the focus, vertex, and directrix  x2 = -12y  y2 = -14x  1/8 ( x - 2)2 = (y + 3)

Q: The focus of the parabola y^2 = 4x is at

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Q: Find the standard form of the equation of the parabola with the given characteristics. focus: (2, 2)…

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Q: Find an equation of the parabola whose graph is shown. y Focus 2 7 2

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Q: Find the vertex, focus and directrix of the parabola given by y2 + 2y + 4x - 7 = 0.Then graph the…

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Q: Find the focus, directrix, focal diameter, vertex and axis of symmetry for the parabola 23.12x=y^2

A: Given: The parabola is 23.12x=y2.   Calculation: Comparing with y2=4ax, we get 4a=23.12a=5.78…

Q: Graph the parabola. Y = (x – 4)^2 + 1. Plot five points on the parabola: the vertex, two points to…

A: Given query is to graph the parabola.

Q: Write the equation for a parabola with axis of symmetry: x=3, focus: (3, -1) and directrix: y=-7.

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Q: Write the equation of a parabola whose directrix is y = 0.25 and has a focus at (-1, - 2.25).

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Q: Find focus of the parabola y=1/2-x-1/2x^2

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Q: find the equation of the parabola with the given properties. Focus (0, 4), directrix y = −4

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Q: Find the focus, directrix, focal diameter, vertex and axis of symmetry for the parabola - 31.2x = y

A: The equation of a parabola y2=-31.2x Comparing with the standard equation y2=4ax4a=-31.2a=-7.8 Focus…

Q: Determine the graph of the second degree equation x? + y² – 6y + 2x + 10 = 0. NONE OF THESE…

A: We have to choose option

Q: Find the focus and directrix of the parabola given by y2 = 12x. Then graph the parabola.

A: y2=12x Now comparing with y2=4ax, we get 4a=12⇒a=3 Therefore focus is, a, 0=3, 0 & directrix is,…

Q: Determine the vertex, focus, directrix, and axis of symmetry of the parabola with the equation y =…

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Q: 1. Write the equation into the standard form of the equation of the parabola: y? – 2y = 8x - 1.…

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Q: Find the vertex, focus, directrix, and axis of symmetry of the parabola. (y+1)² =2(x- 5)

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Q: 3. Find the coordinates of the vertex, focus, and the equation of axis of symmetry with equation y =…

A: Topic = Parabola  As per guidelines, At a time only one question can be answered out of different…

Q: Write the equation of a parabola whose directrix is y = - 0.75 and has a focus at (– 8, 8.75).

A: Let's find.

Q: Find the standard form of the equation of the parabola with the given characteristics. y 1아 Vertex…

A: The equation of a parabola in vertex form: y=(x-h)2+k  Where the vertex is at (h,k) and the focus is…

Q: What is the focus of the following parabola? (y + 5)² = -12 (x - 2)

A: Given,  (y+5)2=-12(x-2)

Q: Write the equation of a parabola whose directrix is y = 9 and has a focus at ( – 10, – 5). |

A: Given (-10, -5) is the focus and y=-9 is the directrix of parabola. Let x0, y0 be any point on the…

Q: Change y -4x+x +6y=2 into standard form. Identify the graph parabola. as an ellipse, circle,

A: Consider the given equation y2 – 4x + x2 + 6y = 2 We observe that the coefficients of squared terms…

Q: Graph the parabola by finding the vertex, directrix, focus, and Latus Rectum. 4. y2-16y-12x +40 = 0…

A: we have to find the following

Q: Find the focus, the directrix, and the vertex of the parabola x^2 − x + 3y − 2 = 0

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Q: Graph the parabola y2 - 2x - 2y - 5 = 0. Give the location of the focus and the directrix.

A: We have to graph the parabola and we have to give the location of the focus and the directrix where…

Q: Identify a and b for the hyperbola with equation a2 y? 1. 62 - a = b = %D

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Q: Find the focus of the parabola. -x- 6x+3y- 15=0 OD

A: If you like the solution then please give it a thumbs up.... The Answer is:           Result:  Focus…

Q: graph the parabola  and determine the focus, vertex and directrix  (3y - 6)2 = 36(x - 2)  x2 + 6x…

A: As we know that the the standard equation of the horizontal parabola is: y-k2=4px-h Where:  Vertex:…

Q: The Focus and the Directrix of the parabola (x – 8)² = 8(y – 3) are -

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Q: Find the focus of the parabola. -x+2x+ 5y-6=0 OD

A: Given query is to find the focus of the parabola.

Q: Which is the equation of the parabola with focus (0, 8) and directrix y = – 8?

A: We will use the fundamental property of parabola.

Q: help in 30mins pls

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Q: Write the equation of a parabola whose directrix is y = 7.5 and has a focus at ( – 4, – 4.5). -

A: The equation of parabola whose directrix is y=-7.5 and has a focus at (-4,-4.5).

Q: Which is the standard equation of the parabola in the graph? Directrix 2 Focus Axis T قمة [cy…

A: To find the standard equation of the given parabola

Q: Find an equation for the parabola with focus  (3, 4)  and directrix the x-axis

A: Focus and directrix are known. Based on that we have to derive the equation of the parabola.

Q: Find the vertex, focus, and directrix of the parabola. y? – 4y – 2x - 4 = 0

A: The given parabola is  y2 - 4y - 2x - 4 = 0

Q: Find the vertex, focus, foci and directrix of the parabola (x-6)^2+8(y+7)=0 and sketch its graph

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Q: Q: Find the vertex, focus, and directrix of the parabola and sketch its graph, for the following…

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Q: The focus of the parabola y? + 8x = 0 has coordinates

A: Option (4) is true

Q: Determine the equation of the parabola, focus (-3/2,3) and directrix at x=-37/2.

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Q: Determine the equation of a parabola given the focus at (-3/2,3) and directrix x=-37/2. Graph.

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Q: Find an equation of the parabola with focus (15/2, 0) and directrix x= -13/2

A: The vertex will be the midpoint of (15/2, 0) and x= -13/2 So, vertex is:

Q: Find an equation of the parabola whose graph is shown. 14x y 7 Focus X 7

A: The given parabola is open left and symmetric about x-axis with vertex at origin. So,  The form of…

Q: Find the x-intercepts of the parabola given by the equation. (If an answer does not exist, enter…

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Q: Find the vertex, focus, and directrix for the parabola (x−1)2=−8(y−3)

A: Vertex form of parabola :  y = a( x - h)2 + k

Q: Find the vertex, focus, and directrix of the parabola (x − 6)2 − 2( y + 7) = 0, and sketch its…

A: Given: The equation of the parabola is, x-62-2y+7=0 The above equation can be converted into vertex…

Q: Find the vertex focus focal width and equation of the axis for each parabola. y^2+8y+4-6x+0

A: Given: y2+8y+4-6x=0 for finding given values, first we convert given equation in standard form of…

Q: (x – 4) = –12 (y + 3) - Find the vertex, focus, and directrix of the parabola.

A: The given equation is: x-42=-12y+3                                     (1)