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GRAPHICAL SOLUTION - CORNER POINT SOLUTION METHOD: BEAVER CREEK EXAMPLE(16 of 18) Maximize Z = $40x₁ + $50x₂ subject to: 1x, + 2x₂ ≤40 4x + 3x₂ ≤ 120 X₁, X₂ ≥ 0 40 30 2044 10 x₁ = 0 bowls -20 mugs Z-$1,000 10 20 x,-24 bowls X-8 mugs Z=$1,300 How many mugs must be produced to maximize profit? a. 20 b. 8 c. 0 B X, 30 bowls -0 mugs Z-$1,200 40 Solution at All Corner Points

GRAPHICAL SOLUTION - CORNER POINT SOLUTION METHOD: BEAVER CREEK EXAMPLE(16 of 18) Maximize Z = $40x₁ + $50x₂ subject to: 1x, + 2x₂ ≤40 4x + 3x₂ ≤ 120 X₁, X₂ ≥ 0 40 30 2044 10 x₁ = 0 bowls -20 mugs Z-$1,000 10 20 x,-24 bowls X-8 mugs Z=$1,300 How many mugs must be produced to maximize profit? a. 20 b. 8 c. 0 B X, 30 bowls -0 mugs Z-$1,200 40 Solution at All Corner Points

College Algebra (MindTap Course List)
College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter6: Linear Systems
Section6.8: Linear Programming
Problem 36E
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GRAPHICAL SOLUTION - CORNER POINT SOLUTION METHOD: BEAVER CREEK EXAMPLE(16 of 18) Maximize Z = $40x₁ + $50x₂ subject to: 1x₁ + 2x₂ ≤40 4x₁ + 3x₂ ≤ 120 X₁, X₂ ≥ 0 a 40 C 30 2044 10 0 x₁ = 0 bowls x₂ = 20 mugs Z-$1,000 10 20 How many mugs must be produced to maximize profit? a. 20 b. 8 c. 0 x, - 24 bowls x₂ = 8 mugs Z= $1,300 B 30 x₁ = 30 bowls x₂ = 0 mugs Z-$1,200 40 Solution at All Corner Points x₂
Transcribed Image Text:GRAPHICAL SOLUTION - CORNER POINT SOLUTION METHOD: BEAVER CREEK EXAMPLE(16 of 18) Maximize Z = $40x₁ + $50x₂ subject to: 1x₁ + 2x₂ ≤40 4x₁ + 3x₂ ≤ 120 X₁, X₂ ≥ 0 a 40 C 30 2044 10 0 x₁ = 0 bowls x₂ = 20 mugs Z-$1,000 10 20 How many mugs must be produced to maximize profit? a. 20 b. 8 c. 0 x, - 24 bowls x₂ = 8 mugs Z= $1,300 B 30 x₁ = 30 bowls x₂ = 0 mugs Z-$1,200 40 Solution at All Corner Points x₂
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