h=-16(2)^(2)-30(2)+220, where h_(0) is the height of the object when t=0 and v_(0) is the velocity of the object at time t=0 (c) How far does the rock fall in 2 seconds if you throw it downward with an initial velocity of 30 feet per second?

h=-16(2)^(2)-30(2)+220, where h_(0) is the height of the object when t=0 and v_(0) is the velocity of the object at time t=0 (c) How far does the rock fall in 2 seconds if you throw it downward with an initial velocity of 30 feet per second?

Name: h=-16(2)^(2)-30(2)+220, where h_(0) is the height of the object when t
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Description: h=-16(2)^(2)-30(2)+220, where h_(0) is the height of the object when t=0 and v_(0) is the velocity of the object at time t=0 (c) How far does the rock fall in 2 seconds if you throw it downward with an initial velocity of 30 feet per second?

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter2: Representing Motion

Section2.4: How Fast?

Problem 29PP

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