Question
Asked Dec 16, 2019
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A graph of position versus time for a certain particle moving
along the x - axis is shown in Figure P2.6. Find the instantaneous
velocity at the instants (a) t = 1.00 s, (b) t = 3.00 s,
(c) t = 4.50 s, and (d) t = 7.50 s.

х (m)
10
8
t (s)
_i 2 3 4 5 678
-2
-4
-6
Figure P2.6
6420
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х (m) 10 8 t (s) _i 2 3 4 5 678 -2 -4 -6 Figure P2.6 6420

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Expert Answer

Step 1

Instantaneous velocity of a particle is equivalent to the slope of the distance time graph.  The expression for the Instantaneous velocity is:

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dx v = dt

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Step 2

(a)

Take the points at t = 0 s and t = 1 s, the plot is straight line. So, these two points can be taken in order to find the slop of the graph that is the instantaneous velocity at time t = 1 s.

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V15 5 m –0 m 1s-0 s 5 m/s

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Step 3

(b)

Take the points at t = 2 s and t = 3 s, the plot is straight line. So, these two points can be taken in order...

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X35 - X25 7.5 m – 10 m 3 s- 2 s |-2.5 m/s ||

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