х+ sin 2x lim х-2 х — sin 2x

Q: sin(2x) lim x→0 sin(7x)

A: This is infinity/infinity form, apply L-Hospital rule to proceed further.

Q: 1) sin 9) tan-1 (-V3) 11) sin- 2

A: Given! 7)sin-1(-1/2) 9) tan-1(-√3) 11) sin-1(-√2/2). Repost the next parts.

Q: sin? 0 sin 2x tan´ x 2. limøseco 3. lim 0→0 1 – cos 40 4. lim- x→0 sin 3x 5. lim -

A: Solution

Q: х+ sin 2x lim х-2 х — sin 2x O 2 О 13 O -3 О 12 O other:

A: To find: limx→2 x+sin2xx-sin2x

Q: sin 5x 6. lim x→0 sin 10x

A:

Q: lim 0→0 sin²0

A: here we have to find the A=limθ→0θsin2θ

Q: evaluate the limit.

A:

Q: 1- sin0 lim а) 1+ cos 20 2

A:

Q: sin(8n) an 1 + Vn lim an %3D

A:

Q: 3 lim 2 x2.tan=.sin- X-00

A: We have to evaluate limx→−∞x2⋅tan2x⋅sin3x It can be written as…

Q: (sin 3x)(sin5x) 12. lim 7x2

A:

Q: () 1 (k) I-3 (1) sin(@)- sec2(0)

A:

Q: lim 3X Sin 13

A: This is of indeterminate form.

Q: sin(x) 4. lim x→0 1 – cos(2x)

A: The solution of the problem is given in the next step.

Q: lim (3x + 1) sin(2x) 4x2

A:

Q: lim x →3 (x − 3) tan(9 — x²) sin²(2x - 6)

A:

Q: 1. حل المعادلة 0 sin 30 = sin لجميع قیم 0 x2 -2 lim 2. أوجد النهاية أن امكن 2- "ر

A:

Q: 22. lim cos2 (x - tan x) cos 2x - 1 sin x 24. lim

A:

Q: lim x→0 x⁹⁹ sin (7x) (sin x) 100

A:

Q: lim 2 sin(-2 x) 0.3) 4 sin (5 x)

A:

Q: sin6x 3 - lim 0 sin2x O 1/3 O 1/2

A: Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: Evaluate the limit.

A:

Q: sin(3 – x) lim x→1 x2 – 5x + 6

A: Explained below

Q: sin20 6. ) lim tan³0 0- 4

A: Given: limθ→π4sin2θtan3θ

Q: sin 14x lim x-0 sin 7x 3x (7x – 2) lim x+0 \7x + 3.

A: limx→0sin14xsin7xAs we know that if limx→a-f(x)=limx→a+f(x)=Llimx→0sin(14x)sin(7x)=00This is…

Q: sin 3x 1. Find lim x→0 sin 4x

A: Hello, thank you for the questions. We’ll answer the first question since the exact one wasn’t…

Q: Evaluate the limit.

A: To evaluatelimx→0sin5xsin2xsin3xsin5x

Q: X 1 sin x+sin 2x Q3/ Find the value of (x) if 5 -2 1= lim %3D 3x -1 2 1

A: We will seperately find the determinant and the limit. Then, we will equate them to solve for x.

Q: sin(3x) 6)lim x→0 sin(4x)

A: We have to evaluate the value of limx → 0 {sin(3x)/sin(4x)}

Q: sin 2x Find lim 3x

A: given equation     limx--> 0    sin(2x)/3x   ** L hospital rule :-   limx-->0  f(x) / g(x) =…

Q: sin 4x2 lim 1 cos 6x

A:

Q: Find the limit.

A: Make two parts of the expression. And distribute the limit with both parts as shown:

Q: sin2 x cos2 4. sin x- cos4 x X - - 1 4

A: To prove that the left-hand side is equals to the right-hand side.

Q: i) lim 5 sin x %3D

A:

Q: sin(16x) cos(8x) =;(sin( x) + sin( -8 2))

A: Let the given trigonometric function be y - y = sin(16x)cos(8x)Divide and multiply by 2 on the right…

Q: sin(5x) е. lim х>0 sin(3x)

A:

Q: sin (3t) (d) lim 1-0 sin (8t) sin (x-4) (е) lim x→4 х—4 cos (2z)-1 (f) lim-

A:

Q: sin(3) (x – 6) – 3sin(x – 6) lim x-6 (x – 6)2 + 2(x – 6) + 3 – 3e*-6

A: We have to find the limit.

Q: sin 0 (1) Lim %3D

A:

Q: sec2 (0) S tan (0)-484

A: To find out the integration.

Q: sin 3x 39.lim tan 6t 41. lim 50 sin 21

A: We will use the l'hospital rule to fine the limit of 39.  To fine limit 41. We will use the basic…

Q: sin 7x 9. lim 9.h x→0 sin 3x

A: GIVEN limx→0sin7xsin 3x

Q: Find the limit.

A: Evaluate: limx→0 sin 4xsin 6x

Q: 4. lim sin2ß B-0 sin3ß

A:

Q: Sin²X+SIN 2X 1)Lim 5X x → 0

A: Here we find limit

Q: evaluate the limit.

A:

Q: sin(4.x) Find lim 1-0 tan(2x)

A:

Q: sin 7x 2: lim 0 4x

A: Topic = Limits

Q: Sin 3x = 3sinx - 4sin'x

A:

Q: sin x 25) lim x→0 5x 3(1 – cos x) 26) lim sin x (1 – cos x) 27) lim 2x2

A: