X 1 sin x+sin 2x Q3/ Find the value of (x) if 5 -2 1= lim %3D 3x -1 2 1

Q: X- 2 sin 5x 1. lim x2 x-4 2. lim 70 5x2-3x x'-1 4. lim 114r 3. lim X00 7x + 1 7)

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Q: 9. Lim 6x - Sin 2x メ→0 2x +3sin 4X b. lim x²-1 1/2

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Q: 5. x sin 3) lim00 x+1

A: limx→∞x5sin5xx4+1=limx→∞ x5sin5xx41+1x4= limx→∞ x sin5x1+1x4 = limx→∞  sin5x1x1+1x4=limx→∞ 5…

Q: limx-->0 sin3x/ex-1

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Q: lim x-->0 (sin(2x^3))/(3x^2)

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Q: х-tanx 2. lim х30 1-со 3 3. lim sinx lnx = 0 x→0+

A:

Q: (2) 1: limx-1 sin(x3–1) x-1

A: limx→1 (2-1x)2sin(x3-1)x-1=limx→1 (2x-1x)2sin(x3-1)x-1=limx→1 4x2-4x+1x2sin(x3-1)x-1=limx→1…

Q: 1-sinx x-1-cos2x 9) lim 10) lim TC X- sinx-cosx TL X- 4

A:

Q: sin(4x) 8. Compute lim x-0 tan(3x)

A: The solution are next step

Q: Зx2-14х +8 lim 7x-28 x+4

A: By factoring method: Take factors in numerator and denominator  Limx-4(3x2-14x+8)/(7x-28)         =…

Q: cos x lim X-0 x2-x+3 lim 1-vx-6 x-7 x-7 X+7

A: We have to find out limit

Q: -lim COS X tanx <-2メ X-8 2 lim 3 x→2 x42x +X-2 A

A:

Q: Q4: A) solve: 1+xsin 1) lim- y0 1+xcos sin 2) lim -2m 20-4

A: Note: We are entitled to solve only one question at a time. To Find: i. limy→01+xsin1x1+xcos1xii.…

Q: lim tan^-1 x divided by x where x is 0 would that be considered undefined?

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Q: x-sin 2x Find lim 2х

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Q: x2-4 1) lim x-2 x-2 sin 2x 2) lim 1 1 3) lim(-- X-0 x VX

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Q: xtan x Solve for the lim X0 sin 3x

A: Given : limx→0x tanxsin3x   To find : Solution of the given limit?

Q: b) lim sin(x² – 4) х* -16 2х - 3 а) lim %3D V3x² +16 x->2 X->-0

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Q: l = lim x→0+ In(x)

A: No, its wrong. you are correct limx→∞ln(x)=-∞…

Q: x2 – lim x + sin x 2x x→0

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Q: (1 – V3x lim tan- 3 + x x-00

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Q: In(sin 4x) \ In(sin 8x) lim x → 0

A: We have to evaluate the limitlimx→0ln(sin4x)ln(sin8x)

Q: 3. Find lim x sin II

A: Given limx→∞xsin(πx)

Q: Inx lim X+o x3 lim- x-0 ex - x2 - 1 lim- 0 sin'3x

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Q: 5. lim V2x +1 X-4 6. lim -) ズー1 x-1 CABA 3x+4 if x <-3 AT 7. lim f(x), where f(x) = 2-4 ifx2-3

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Q: cos x-2sinx 1. limx-n 3cosx -2 limx-3 X-3 3x6-x*+2x-3 limy--o 4x5+2x3-5 iv. lim,→-1(x³ limy--1(x³ –…

A: [i]

Q: 2x-arcsinx 7. lim x→0 2x+arctgx emx. 8. lim х-0 пх In(1+3*) 9. lim x→-o In(1+2*)

A: There are multiple question so as per Bartleby policy  I have answered two question, Kindly ask…

Q: 2. lim x sec 2x

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Q: 2tan 'x -x (-) 2x – sin 'x 02. lim, -1

A: Given limx→02tan-1x-x2x-sin-1xTo evaluate the limit:

Q: (1) lim,-0 √x+9-3 X (2) lim-0 1–c05x x sinx (3) limx-1 x²+3x-4 x-1

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Q: 2. lim x sin(1/x) X18 ex+2x 3. lim X18 ex

A:

Q: 1) lim-sinxr x-0

A: given equation is     limx--&gt;0  (x-sinx) / x³ ** L hospital rule =&gt;    limx--&gt;0  f(x) /…

Q: 2) lim sin 4x

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Q: 2- x - sinx 1. lim x00 x + cosx x*+2x-1 2. lim-0 x3-2x2+x

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Q: Question 3 arctan(3x) lim ( Select) X--0 ex -1 1/x lim x--0+ In x ( Select)

A: to find:- limit.

Q: find lim x-> 0, cos (12x)-1 / 3x

A: Given,              limx→0cos 12x - 13x Move the term 1/3 outside of the limit because it is…

Q: x²+1 4.limx→0 x+cosx 1 х3—1 5.limx→1 х-1 9 – x2 maa - 6. lim x→3 V3 + 2x – x² x4-16 7.limx→2 V x³-8

A: according to our guidelines we can answer only three subparts, or question and rest can be…

Q: 2Tan 'x - x 9. lim,0 'x0 2x – Sin 'x

A:

Q: x3–1 х-14x3-х-3 1) lim sin 2x 2) lim x→0 2x²+x 3) lim 1-v х-1 1-х

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Q: Find the value of : sin3x lim x→0 2x

A: This question is based on Limits.

Q: 1-cos (4x) e) lim x0 2-2cos (6x) (x+1)2 + (2x+3)³ 3x2(8x+1) h) lim X00

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Q: cOs x tan x 28) lim x→0 sin 3x 29) lim x→0 2x x3 + 2x2 + x 30) lim x→-1 x4 + x3 + 2x + 2

A: As per our guidelines we need to solve only 3 questions .please repost the remaining subparts as…

Q: 5 sin(6x) lim x→0 3x

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Q: V+12-4 3 .lim X-2 tan3x 2. lim X-0 sinax 4). lim X00 x-7x+1 x-2

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Q: 1 - cosh x lim x→0+ ln(x² + 1)

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Q: limx→0 sin 2x 2x²+x

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Q: ¶/x x-0 sin (1 /x) Lim

A: To evaluate: limx→∞π/xsin(π/x)

Q: 2x (1) lim x→0 3– vx+ 9 -

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Q: 2+ sec (3x) (с) lim я (6 tan (3x) —1

A:

Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topics, such as continuity and differentiability better. In a broader sense, every calculus notion is a limit. Other branches of calculus have also been derived from limits.