H.W 1. Consider a two degree of freedom bar elements as shown in figure. Using finite element method to formulate the equilibrium equation of it. If the cross sectional area is 12 mm and E=200 GN/m². 20KN 15KN * 350 -30KN 300+ 600- All Dimension in mm

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter2: Axially Loaded Members
Section: Chapter Questions
Problem 2.3.10P: A two-story building has steel columns AB in the first floor and BC in the second floor, as shown in...
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H.W
1. Consider a two degree of freedom bar elements as shown in figure. Using finite
element method to formulate the equilibrium equation of it. If the cross
sectional area is 12 mm and E=200 GN/m².
20KN
+30KN
15KN
300 *
600-
+ 350
All Dimension in mm
2. Consider a two degree of freedom bar element as shown in figure. Using finite
element method to formulate the equilibrium equation of it, and then estimate
the stress distributions. If Esteel-200 GN/m, Ecopper 110GN/m and EAL= 120
GN/m?.
d=3
Steel
AL
Соpper
20KN
- 30KN
→15KN
300 * 200 - 400 * 350
All Dimension in mm
Transcribed Image Text:H.W 1. Consider a two degree of freedom bar elements as shown in figure. Using finite element method to formulate the equilibrium equation of it. If the cross sectional area is 12 mm and E=200 GN/m². 20KN +30KN 15KN 300 * 600- + 350 All Dimension in mm 2. Consider a two degree of freedom bar element as shown in figure. Using finite element method to formulate the equilibrium equation of it, and then estimate the stress distributions. If Esteel-200 GN/m, Ecopper 110GN/m and EAL= 120 GN/m?. d=3 Steel AL Соpper 20KN - 30KN →15KN 300 * 200 - 400 * 350 All Dimension in mm
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