H.W The comPound shaft Shawn is attached to vigid. Surhrts, for the branze Segment AB, the oliameter is 75mm, G=35.GNIm and Ts 60 MN/m. for steel Segment Bc, the diameter is somm, G= 836Nim and TS8o mNIm If a= 2m anl b= 1.5m,lomPate the maximum torquelT ) that Ganbe npiied? UT 9. 9.
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- H.W A Solid Steel bar of dlameter 6omm and length 350 mm is Placed inside an aluminum cylinder öf Inside diameter Femm and out side d lameter Ilomm, a comPressive load of looo lais applied on the assembly, find the stresses in the bar and the cylinder ? take Est = 200GPa and EAl = F0GPan %3D Cover Plate 0.25mm d- do 35omm A lum. cylinder Steel bar7 Enercise:- 30 long with is subjected to a Assuming deformation is entirely elastic and manimum allowable elongation tensile 30000y that the is 0.3 mm while manimum. allowable reduction in, digmeter is 0.015mm. choose amory below only. candidate meeting requirent E (GPa) A cylindrical rod 100 mm diameter of 12 mm load of 30000 N. Aluminium alloy Bronze Titanium allow 70 100 110 U(Poiss ons vahi) 0.33 0.34 0.32- A 2m COPPER BAR SUBJECTEO TO A TENSILE IS SUSPENDED FROM A LOAD IBO KN SUPPORTED BY TWO IDENTICAL PIN THAT S pOSIS AS SHON OF THE LOWER AFPLIED TENSILE POSTS SUPPORT THE STEEL DETERMINE THE TOTAL DEFORMATION END OF THE LOAD HINT: NOTE THAT THE STEEL PIN WHERE THE COFPER BAR IS ATTACHED. COPPER BAR DUE TO STEEL POST L=0.5m A= 4500mm E- 200GPA COPFER BAR L- am A= 4800 Mn E- l20 GPa 180KN
- أ.د. رمضان المبروك A PL170mm x 10mm tension member is welded to a gusset plate as shown in Figure below. The steel is A36. Assume that Ae = Ag and compute the following. %3D fy = 250 MPa & f, = 400 MPa %3D %3D PL 170mmx10mm a. The design strength for LRFD. . The allowable strength for ASD. roblem (4):10/10 find the tensile stress in upper plate in section 3-3 80 kN 80 kN 8-bolt DIA. 10 MM 80 kN 80 kN 8-bolt DIA. 10 MM 10 MPа О 12.5 MPa 15 MPa 8.5 MPa O no one O ---.. O- O O 300mm 8 mm10 mm 20 mm The assembly above is comprised of a 10mm-diameter steel bolt, and a 20mm-diameter, 2mm-thick bronze sleeve. The bolt and sleeve are rigidly connected at each end by a washer. Assume the following properties: Epolt = 29000 ksi &bolt = 6.6-106 1°F Vbolt = 0.35 Member BC is made of bronze with the following properties: Esleeve = 15000 ksi Xsleeve =9.80-106 /°F Vsleeve = 0.35 If the assembly is heated up, which of the following statements best describes how the sleeve will be affected? The sleeve will try to expand longitudinally, but will be restricted by the bolt (because the bolt has a lower coefficient of thermal expansion). The sleeve will go into tension and the bolt will go into compression. O The sleeve will try to expand longitudinally, but will be restricted by the bolt (because the bolt has a lower coefficient of thermal expansion). Both members will go into tension. The sleeve will try to expand longitudinally, but will be restricted by the bolt (because the bolt…
- 8. H / The beam shown below has across seclion of channel Shape with width 360mm.and haghs h= loomm, the web thickness ist= 14mm.Deler- Mine ihe Max imum tensile aud Compressive stressin the beam due to unifom Load? 360Mm 3.6KN/M 14m tiom Please Sir 5T CASIC f-991ES PL DATURAL u CALC (-)De term ine the kin d and am ount of stress in e ach mem ber of the truss shown by the method of jo in ts in figure P 5-2 (page 76).- 1000lb 1000lb 1000lb 1000Ib 1000 Ib U. h = 20 ft 500lb 500 Ib L. L. RAV 6 pane ls at 10' - 6 ft RBy Note: 1. F o llo w strictly the lecture notes g iv en. Draw the FBD of e ach jo in t 2. Sum m a rize and tabu la te your answers. 3. Compu te the bar forces up to member U,L3 on ly because the truss lo a d in g is sym metric aland the bar forces of right sid e members are id en tic al w ith th e left s ide members. But you in c lu de th e rig ht sid e mem bers in have to the tabu la tion. 4. Show the com puta tio n ho w the leng th s were obta in ed. 5. Look for your own data in the table provided. 6. Copy the problem , data of problem and fig ure of the proble m TABULAT ION FOR SUMMAR Y OF COMPUTATION OF BAR FORCES METHOD OF JOINTS (PROBLEM P5-2 PAGE 76) Mem ber Identification Length Bar Forc e Туре of ft Ib force LOL1 10 3750 Tensio n L1L 2 10 Tension…Ro blem 2 20" го Given Base Rate A36 (Fye36 Ksi) WI2X5 20" B= N= 20 in t= 17/2" W 12 x 50 (de12.2", bf: 8.08 in) fc: 5 ksi A= A2 Determine the max Tu that Can be applied to this base Plate ? biet: ) determine u banaal on A, (2) Chorse the Smaller af tw valus
- H.W The omPound shaft Shown isattached to Kigid SuPprts, for the bronze Segment AB, the diameter is 75mm G=35 GN/m and TS60MNIM. for steel Segment Bc, the dlameter is Somm, G= 836N/mand TS8OMNIMIF a=2m and b= 1.5m,lam Pute the maximum torguelT) that Gan be applier?3. Determine the maximum tensile capacity of a L 178 x 102 x 19 angle as shown below if bolt diameter = 24 mm. The long leg of the member is connected to a 24mm thick guest plate. Use A572M gr.345 steel material. Ta 76 → 76 V L178x102x19 mam 76 76 5 38 4. The tension member shown below is a C 310 x 30.8 of A572M gr 345 steel materials. Will it safely support a service dead load of 265 kN and a service live load of 555 kN.Homework: A helica) cast steel with 3. helix angle has to tanmiz 35 KW at 1500 YPu. Gear has 24 teeth, 2 full depth. Tha Static Stress for Cast Steel maybe taken as 56 Mpa.. The width. of face may be talcen as 8 time) th module. Assum e : Cs =l, Ep=E= Ges=300 HPa , be =60 MPa, Calculate: WA, WNm, b, VR, = 200G Pa C=40.