H2(g) + 12(g) = 2HI(g) (= is equilibrium sign)At particular temperature, The equilibrium constant (K) = 100If 1.0 mole of H2, 1.0 mol of I2 and 1.79 mol of HI are introduced into 1.00 L container. The concentration of HI whenequilibrium is reached isWrite your answer to 1 d.p e.g 7.6Answer:

Answered: Image /qna-images/answer/7e4bf676-20cc-47cb-b148-e0aeda4f5f1f.jpg

H2(g) + 12(g) = 2HI(g) (= is equilibrium sign) At particular temperature, The equilibrium constant (K) = 100 If 1.0 mole of H2, 1.0 mol ofl2 and 1.79 mol of HI are introduced into 1.00 L container. The concentration of HI whe equilibrium is reached is Write your answer to 1 d.p e.g 7.6 Answer:

H2(g) + 12(g) = 2HI(g) (= is equilibrium sign) At particular temperature, The equilibrium constant (K) = 100 If 1.0 mole of H2, 1.0 mol ofl2 and 1.79 mol of HI are introduced into 1.00 L container. The concentration of HI whe equilibrium is reached is Write your answer to 1 d.p e.g 7.6 Answer:

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter14: Chemical Equilibrium

Section: Chapter Questions

Problem 14.19QE: At 2000 K, experiments show that the equilibrium constant for the formation of water is 1.6 1010....

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Question

H2(g) + 12(g) = 2HI(g) (= is equilibrium sign)
At particular temperature, The equilibrium constant (K) = 100
If 1.0 mole of H2, 1.0 mol of I2 and 1.79 mol of HI are introduced into 1.00 L container. The concentration of HI when
equilibrium is reached is
Write your answer to 1 d.p e.g 7.6
Answer:

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