H2(g) + I2(g) → 2HI(g) I was given this problem: A student makes the following statements: Hydrogen always has the same oxidation number, so it has an oxidation number of +1 in both the reactant H2 and product HI. Iodine is in Group VIIA, so it has an oxidation number of –1 in both the reactant I2 and product HI. Neither hydrogen nor iodine changes oxidation states, so the reaction is not a redox reaction. How can I describe the mistake that the student made, and determine whether or not the reaction is a redox reaction.

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter17: Electrochemistry And Its Applications
Section: Chapter Questions
Problem 11QRT
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H2(g) + I2(g) → 2HI(g)

I was given this problem:

A student makes the following statements:

  • Hydrogen always has the same oxidation number, so it has an oxidation number of +1 in both the reactant H2 and product HI.
  • Iodine is in Group VIIA, so it has an oxidation number of –1 in both the reactant I2 and product HI.
  • Neither hydrogen nor iodine changes oxidation states, so the reaction is not a redox reaction.

How can I describe the mistake that the student made, and determine whether or not the reaction is a redox reaction.

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