H2(g)+Br2(g)→2HBr(g) Kc = 2.00 x 10^4 At equilibrium, there are 0.140 moles of H2 and 0.144 moles of Br2 in a 1.00 L container. What is the concentration of HBr in mol L-1
H2(g)+Br2(g)→2HBr(g) Kc = 2.00 x 10^4 At equilibrium, there are 0.140 moles of H2 and 0.144 moles of Br2 in a 1.00 L container. What is the concentration of HBr in mol L-1
Chemistry for Engineering Students
3rd Edition
ISBN:9781285199023
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.54PAE: Consider the following system: 4NH 3 ( g )+ 3O 2 ( g ) N 2 ( g )+ 6H 2 O( l ) H=1530.4kJ (a) How...
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The reaction between H2 and Br2 produces HBr, as shown below
H2(g)+Br2(g)→2HBr(g) Kc = 2.00 x 10^4
At equilibrium, there are 0.140 moles of H2 and 0.144 moles of Br2 in a 1.00 L container. What is the concentration of HBr in mol L-1?
Give your answer to the correct number of signficant figures
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