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H2O (1) + SO2(g) SO2(g) 20 (1) ArH=-562.3 kJ/mol ArH=-297.0 kJ/r ArH=-266.9 kJ/

H2O (1) + SO2(g) SO2(g) 20 (1) ArH=-562.3 kJ/mol ArH=-297.0 kJ/r ArH=-266.9 kJ/

Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter16: Thermodynamics: Directionality Of Chemical Reactions
Section: Chapter Questions
Problem 83QRT: Another step in the metabolism of glucose, which occurs after the formation of glucose6-phosphate,...
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Given the following data: H2S(g) + 3/2O2(g) → H2O (1) + SO2(g) 1/8 Sg(s) + O2(g) → SO2(g) H2(g) + 1/2O2 → H2O (1) -> Compute ArHº for H2(g) + 1/8 S8 (s) → H2S(g) in kJ/mol. - a) 265.3 kJ/mol Ob) 562.3 kJ/mol Oc) -1.6 kJ/mol O d) 276.6 kJ/mol e) 20.5 kJ/mol ArH=-562.3 kJ/mol ArH=-297.0 kJ/mol ArH=-266.9 kJ/mol
Transcribed Image Text:Given the following data: H2S(g) + 3/2O2(g) → H2O (1) + SO2(g) 1/8 Sg(s) + O2(g) → SO2(g) H2(g) + 1/2O2 → H2O (1) -> Compute ArHº for H2(g) + 1/8 S8 (s) → H2S(g) in kJ/mol. - a) 265.3 kJ/mol Ob) 562.3 kJ/mol Oc) -1.6 kJ/mol O d) 276.6 kJ/mol e) 20.5 kJ/mol ArH=-562.3 kJ/mol ArH=-297.0 kJ/mol ArH=-266.9 kJ/mol
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