H3C H H H H NH2 H H Н H Но H Ho H H H HO -OH HO CH3 H- H H H H H H H H H H H H H OH H CH3 OCH3 CH3 H A B C D Drag and drop options on the right-hand side and submit. For keyboard navigation... SHOW MORE ✓ A B III = = III C = III D = III hemi-aminal hemi-acetal hydrate acetal
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Give detailed Solution with explanation needed..don't give Handwritten answer..match the following structures to the functional group present
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- Good hand written explanation Asap Thanks What is an azeotrope? a) A mixture of compounds that is dangerous to distill. b) Any mixture that cannot be practically separated by distillation c) A set ratio of compounds that can only be distilled in the best equipment under the best conditions. d) A set ratio of two compounds (e.g. 5% ethanol in water) that always distills together at the same time.I know there is: 1. Carboxylic group 2. Ester. 3. Ortho-disubstituted phenyl. But my answer is still partial.Q1. What are emulsions? Why do they form during extractions? How is their formation minimized? Q2. Why is it necessary to turn the separatory funnel upside down and to open thestopcock?
- Is there any possible way for Butene (C4H8) ----> Ethanol (CH3CH2OH)? and how about Beneze---> Acetophenone---> Ethanol? Is the only way of getting Ethanol by Ethene---> Ethanol I need to know the organic chemistry mechanisms.this is IR data from acetylsalycilic acid. what are the major diagnostic functional groups shown?...Preparation of para-iodonitrobenzene 1. Weight of p-nitroaniline = 0.552 g 2. Weight of para-iodonitrobenzene = 0.231 g 3. Theoretical yield = ............................................ 4. Percentage yield = ............................................. 5. Melting point range = .................... 0C.
- #B: Methyl acetate has methoxy, -OCH3 as the remaining of the alcohol part in the ester. Isopropyl acetate has isopropoxy, -OCH(CH3)2 as the remaining of the alcohol part in the ester. -OCH(CH3)2 is more electron donating than the methoxy, -OCH3 group due to the presence of two electron-donating -CH3 group in the former. Hence saponification reaction of Isopropyl acetate is much slower than methyl acetate. Hence the rate of saponification of methyl acetate, CH3CCO2CH3 is 50 times greater than that for isopropyl acetate.A student attempted to prepare 1-chlorobutane by mixing 1-butanol with NaCl in acetone. Was the student succesful? Explain.Unknown Results - Solubility Test: - Slightly soluble Ceric Ammounium Nitrate Test: - Positive Iron (III) Chloride Test: - Negative Chromic Acid Test: - Positive Iodoform Test: - Negative Luca's Test: - Negative The known alcohols tested in this experiment are: Ethanol 1-Propanol 2-Propanol 1-Butanol 2-Pentanol 2-Methyl-2-propanol 1-Octanol Phenol Although you didn't carry out every test on all eight alcohols, you should be able to predict the results for the tests on the alcohols that you did not test. If your unknown alcohol is one of these eight known alcohols, which do you think yours is? Can you definitely identify it? Explain your answer using your test results and predicted results.
- An attempted dehydration of propan-1-ol (ch3ch2ch2oh) with H2SO4 at 135 degrees celcius gave a by product C6H14O that when tested gave the following results: Baeyer test: Negative Br2/CCl4 Test: Negative Chromic Acid Test: Negative Propse a strucure for the following odd product and explain its formation(a) Arrange the following compounds in an increasing order of their indicated property :(i) Benzoic acid, 4-Nitrobenzoic acid, 3,4-Dinitrobenzoic acid, 4-Methoxybenzoic acid (acid strength)(ii) CH3CH2CH (Br) COOH, CH3CH (Br) CH2COOH,(CH3)2CHCOOH, CH3CH2CH2COOH (acid strength)(b) How would you bring about the following conversions :(i) Propanone to Propene (ii) Benzoic acid to Benzaldehyde(iii) Bromobenzene to 1-phenylethanolUse the given template to draw three-dimensional line structures of (2S, 5R)-5-amino-2-hydroxylhexanal. Clearly show the three-dimensional arrangement of the substituents on the stereogenic centres.