has two relations ch a is the primary is the primary key nce of P has 70 Tup s 42. What is the m in the new instance
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- Suppose we have three relations r(A, B), s(B, C), and t(B, D), with all attributesdeclared as not null. Give instances of relations r, s, and t such that in the result of(r natural left outer join s) natural left outer join tattribute C has a null value but attribute D has a non-null value.Consider that a database contains the following relations PARENT(X, Y), and a relation BIRTH(X, B), where B is the birthdate of a person X. The following information is used for question (b), (c) that we have the following family treeI need help with the following Consider a STUDENT relation in a UNIVERSITY database with the followingattributes (Name, Ssn, Local_phone, Address, Cell_phone, Age, Gpa). Note thatthe cell phone may be from a different city and state (or province) from thelocal phone. A possible tuple of the relation is shown below:Name Ssn Local_phone Address Cell_phone Age GpaGeorge Shaw 123-45-6789 555-1234 123 Main St., 555-4321 19 3.75William Edwards Anytown, CA 94539a. Identify the critical missing information from the Local_phone andCell_phone attributes. (Hint: How do you call someone who lives in a dif ferent state or province?)b. Would you store this additional information in the Local_phone andCell_phone attributes or add new attributes to the schema for STUDENT?c. Consider the Name attribute. What are the advantages and disadvantagesof splitting this field from one attribute into three attributes (first name,middle name, and last name)?d. What general guideline would you recommend for…
- Suppose we have three relations r(A, B), s(B, C), and t(B, D), with all attributesdeclared as not null. Are there instances of r, s, and t such that the result ofr natural left outer join (s natural left outer join t) has a null value for C but a non-null value for D? Explain why or why not.Consider a relational database for an online hotel booking company. The database consisting ofthe following tables (where the primary keys are underlined): Hotel (hId, hName, hAddress, hCity) Guest(gId, gName, gAddress, gCity) Room(hid, roomNo, type, price) Booking(gId, hId, roomNo, fromDate, year, noOfDays)Where hId and gId are identifiers for the hotels and the guests,and the Booking relation indicated that a guest booked a hotel room for a specified number of days(noOfDays) starting from fromDate of a given year. For instance, a tuple < g12345, h5555, 220,Jan05, 2016, 15> in Booking indicates that the guest g12345 booked room 220 of the h5555 hotelfor 8 days starting on Jan 5, 2016. The attribute "gAddress" records the home address of theguests.Write the following queries in relational algebra (1) Return thename of guests who have booked a hotel room in NYC in January 2016 (i.e.,fromDate between 01/01 and 01/31 and year=2016).(2) Return thename of guests who have booked a…Given the following relation R and its functional dependencies: R(workerNumber, repairNumber, workerName, machineNumber, spentTime, repairDate, machineName, workshopNumber, workshopName ) workerNumber à workerName repairNumber à repairDate, machineNumber machineNumber à machineName, workshopNumber workshopNumber à workshopName 1)Create a database whose tables are at least in 3NF, showing the dependency diagrams for each table
- Consider the following set F of functional dependencies on the relation schema(A, B, C, D, E, G):A → BCDBC → DEB → DD → A Compute B+.Given the following relation R and its functional dependencies: R(workerNumber, repairNumber, workerName, machineNumber, spentTime, repairDate, machineName, workshopNumber, workshopName ) workerNumber à workerName repairNumber à repairDate, machineNumber machineNumber à machineName, workshopNumber workshopNumber à workshopName Explain the types of all the dependencies in the relation R. Create a database whose tables are at least in 3NF, showing the dependency diagrams for each table.Consider a database containing two relations: R(A,B,C) and S(D,E,F). For each of three (your choice) of the 12 rewriting rules for relational algebra expression, give an example pair of relational algebra expressions involving R and S such that the rule rewrites one expression to the other expression, and give another example pair to show the rewriting rule cannot be used since some of the conditions for the rule arenot satisfied
- Suppose we have a relational database with five tables.table key AttributesS(sid, A) SidT(tid, B) TidU(uid, C) UidR(sid, tid, D) sid, tidQ(tid, uid, E) tid, uidHere R implements a many-to-many relationship between the entities implemented with tables S and T, and Q implements a many-to-many relationship between the entities implemented with tables T and U.D. Suppose you replaced SELECT with SELECT DISTINCT in your queries from parts (a) and Could one of these modified queries return more records than the other? If so, which one? Justify your answer. E. Consider again your query from part (a). If pair sid, uid is returned by this query then there must exist at least one “path” that goes from from table S to table T (via relation R) and then from table T to table U (via relation Q). Note that there can be many such paths for a given pair sid, uid. Write an SQL query that returns records of the form tid, total where…Consider a database schema with a relation Emp whose attributes are as shown below, with types specified for multivalued attributes. Emp = (ename, ChildrenSet multiset(Children), SkillSet multiset(Skills))Children = (name, birthday)Skills = (type, ExamSet setof(Exams))Exams = (year, city) Redesign the database above into first normal form and fourth normal form. List any functional and multivalued dependencies that you assume. Also list all referential-integrity constraints that should be present in the first and fourth normal form schemas.DATABASE SYSTEMS 16.Consider a relation R = (A,B,C,D,E) with the following functional dependencies: {C,E → D, D → B, C → A} and identify a candidate key. None of them {C,E,D} {C,E,B} {C,E} 17.A join in which tuples from R1 that do not have matching values in the common attributes of R2 are also included in the result relation. R1 left outer join R2 R1 semi join R R1 equi join R2 R1 natural join R2 18.When two transactions that access the same database items have their operations interleaved in a way that makes the values of some database items incorrect this problem is call? none of them dirty read summary problem the lost update problem 19.Protect the database from inconsistencies and data loss Database recovery Database Transaction & Concurrency control Concurrency control Concurrency control & Database recovery 20.Let E1 and E2 be two entity types in an entity relationship diagram. E1 have all three simple single-valued attributes while E2 have two simple…