What is the matrix form of the corresponding linear system of ODE? For the next three questions, consider the two-tank system shown below. Each of the twotanks contains 200 gallons of water in which fertilizer is dissolved. Let y1 (t) and Y2(t)correspond to the fertilizer content in tank 1 and tank 2, respectively.12 gal/min4 gal/min(Pure water)T16 gal/min12 gal/min

Given, consider the two-tank system shown below. Each of the two tanks contains 200 gallons of water…

Answered: hat is the matrix for

College Algebra (MindTap Course List)

12th Edition

ISBN:9781305652231

Author:R. David Gustafson, Jeff Hughes

Publisher:R. David Gustafson, Jeff Hughes

Chapter2: Functions And Graphs

Section2.6: Proportion And Variation

Problem 18E

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A tank with capacity of 300 gal of water originally contains 200 gal of water with 100 lb of salt in solution. Water containing 1 lb of salt per gallon is entering at a rate of 3 gal/min, and the mixture is allowed to flow out of the tank at a rate of 2 gal/min. Let Q(t) lb be the amount of salt in the tank, V(t) gal be the volume of water in the tank.
Write x'' + y^2y' − x^3 = ?sin(t), y'' +(x' +y')^2 −x? = 0 as a first order system of ODEs.
Consider the cascade of two tanks of brine shown in the figure below, with V1=99 gallons and V2=204 gallons being the volumes of brine in the two tanks. Each tank also initially contains 51 lb of dissolved salt. The three flow rates indicated in the figure are each 4.6 gal/min, with pure water flowing into tank 1. (a) Find the amount x(t) of salt in tank 1 at time t. x(t)=? (b) Suppose that y(t), the amount of salt in tank 2 at time t, is given by the differential equation dy/dt=(4.6x/99)−(4.6y/204). Solve for y(t) using the function x(t) found in part (a) y(t)=?
Consider two tanks T1 and T2 with T1 containing 50 gallons of water in which 25 pounds of salt is dissolved and T2 containing 50 gallons of pure water. Pure water flows from outside into T1 at a rate of 4 gal/min and salt solution is circulated at rates of 6 gal/min from T1 to T2 and 2 gal/min from T2 to T1. If the content of T2 is withdrawn out of the system at the same rate as the pure water to T1 (i.e., 4 gal/min) to ensure no liquid volume change in the system, and the mixture in each tank is well mixed, find the salt contents y1 (t) and y2 (t) in T1 and T2 respectively. Determine the time it would take for the salt contents in the two tanks to be equal.
The radiator car is filled with a solution of 65% antifreeze and 35% water. The manufacturer of the antifreeze suggests that for summer driving, optimal cooling of the engine is obtained with only 50% antifreeze. If the capacity of the radiator is 3.9L, how much coolant should be drained and replaced with water to reduce the antifreeze concentration to the recommended level?
For an auditorium: Room condition: 26oC DPT, 19 oC WPT; Outside conditions: 35 oC DPT 27 oC WPT; Room heat gains: Sensible heat= 11.1 kW Latent Heat= 3.9 kW The conditioned air supplied to the room is 50 cm/min and contains 25 percent fresh air and 75 percent re-circulated room air. Determine; a) The DBT and WBT of supply air. b) The DBT and WBT of mixed fresh and re-circulated air before the cooling coil. c) The apparatus due point in bypass factor of the coil d) The refrigeration load on the cooling coil and the moisture removed by the coil.
Solve the system below for x(t) and y(t). 2dx/dt +dy/dt − x − y = 1 dx/dt +dy/dt + 2x − y = t
Solve the system below for x(t) and y(t). 2dx/dt +dy/dt − x − y = 1dx/dt +dy/dt + 2x − y = t
The radiator in a car is filled with a solution of 55% antifreeze and 45% water. The manufacturer of the antifreeze suggests that for summer driving, optimal cooling of the engine is obtained with only 50% antifreeze. If the capacity of the radiator is 3.3 L, how much coolant should be drained and replaced with water to reduce the antifreeze concentration to the recommended level?
Which of the following could the model for a single-tank mixing problem where pure water is entering the tank? choose : could be more than 1 right answer: dA/dt=4−A/50 dA/dt=4−A/50−t dA/dt=4−A/50+2t dA/dt=−A/50−t dA/dt=A/50−t
Z=4 A=4 NEED Step by step solution in 40minutes.

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