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PhysicsQ&A Libraryhe figure below shows a charged particle, with a charge of q = +38.0 nC, that moves a distance of d = 0.185 m from point A to point B in the presence of a uniform electric field E of magnitude 245 N/C, pointing right. A positive point charge q is initially at point A, then moves a distance d to the right to point B. Electric field vector E points to the right. (a) What is the magnitude (in N) and direction of the electric force on the particle? magnitude Ndirection ---Select--- toward the right toward the left The magnitude is zero. (b) What is the work (in J) done on the particle by the electric force as it moves from A to B? J (c) What is the change of the electric potential energy (in J) as the particle moves from A to B? (The system consists of the particle and all its surroundings.) PEB − PEA = JStart your trial now! First week only $4.99!*arrow_forward*

Question

The figure below shows a charged particle, with a charge of *q* = +38.0 nC, that moves a distance of *d* = 0.185 m from point *A* to point *B* in the presence of a uniform electric field

E

of magnitude 245 N/C, pointing right.A positive point charge *q* is initially at point *A*, then moves a distance *d* to the right to point *B*. Electric field vector **E** points to the right.

(a)

What is the magnitude (in N) and direction of the electric force on the particle?

magnitude Ndirection ---Select--- toward the right toward the left The magnitude is zero.

(b)

What is the work (in J) done on the particle by the electric force as it moves from *A* to *B*?

J

(c)

What is the change of the electric potential energy (in J) as the particle moves from *A* to *B*? (The system consists of the particle and all its surroundings.)

(d)

What is the potential difference (in V) between *A* and *B*?

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