height hTimeTimeMean time tMeant1 (s)t? (s?) h/t2 (m/s?)|h/t2 (m/s²)g (m/s²)(cm)t2 (s)(s)250.2250 0.2256350.2672 0.2474450.3021 0.3029550.3351 0.3357650.3640 0.3650II

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Description: height hTimeTimeMean time tMeant1 (s)t? (s?) h/t2 (m/s?)|h/t2 (m/s²)g (m/s²)(cm)t2 (s)(s)250.2250 0.2256350.2672 0.2474450.3021 0.3029550.3351 0.3357650.3640 0.3650II

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height h Time Time Mean time t Mean t1 (s) t2 (s) t? (s?) h/t2 (m/s?)| h/t2 (m/s?) g (m/s²) (cm) (s) 25 0.2250 0.2256 35 0.2672 0.2474 45 0.3021 0.3029 55 0.3351 0.3357 65 0.3640 0.3650 II

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter2: Representing Motion

Section: Chapter Questions

Problem 48A

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(a) Use the distance and velocity data in Figure 3.64 to find the rate of expansion as a function of distance. (b) If you extrapolate back in time, how long ago would all of the galaxies have been at approximately the same position? The two parts of this problem give you some idea of how the Hubble constant for universal expansion and the time back to the Big Bang are determined, respectively. Figure 3.64 Five galaxies on a straight line, showing their distances and velocities relative to the Milky Way (MW) Galaxy. The distances are in millions of light years (Mly), where a light year is the distance light travels in one year. The velocities are nearly proportional to the distances. The sizes of the galaxies are greatly exaggerated; an average galaxy is about 0.1 MlY across.
A map suggests that Atlanta is 730. miles in a direction 5.00 north of east from Dallas. The same map shows that Chicago is 560. miles in a direction 21.0 west of north from Atlanta. Figure P1.68 shows the location of these three cities. Modeling the Earth as flat, use this information to find the displacement from Dallas to Chicago. Figure P1.68
Quinton can run 12 miles per hour. How many feet can he run per second? A)1mile/5280 B) 1min/60sec C)1hr/60
7. On the planet Zebulon, the standard unit for length is the clorf (cl) and the standard unit for time is the beedle (be). After many years of research, you have determined that 1clort = 0.765 meters 1beedle = 1.957 seconds (1cl = 0.765m) (1be = 1.957s) If you are driving at a speed of 85mi / h , how fast are you going in terms of clorés per beedle (cl/be)? NOTE: 1 mi = 1609 m.
What is the speed of a car going v=1.000mphv=1.000mph in SI units? Notice that you will need to change from miles to meters and from hours to seconds. You can do each conversion separately. Use the facts that 1mile=1609m1mile=1609m and 1hour=3600s1hour=3600s.
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In SI units, speeds are measured in meters per second (m/s). But, depending on where you live, you’re probably more comfortable of thinking of speeds in terms of either kilometers per hour (km/h) or miles per hour (mi/h). In this problem, you will see that 1 m/s is roughly 4 km/h or 2 mi/h, which is handy to use when developing your physical intuition. More precisely, show that (a) 1.0 m/s = 3.6 km/h and (b) 1.0 m/s = 2.2 mi/h. American football is played on a 100-yd-long field, excluding the end zones. How long is the field in meters? (Assume that 1 m = 3.281 ft.)
On an alien world, they measure distance in fleeps and time in florps. If 1.6 fleep =1 m and 5.2 florps = 1 second, how many fleeps/florps is in 10 m/s? How many m/s^2 is 10 fleep/florps?
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How many significant figures are in each of the following? a) 2.401 b) 0.0005337 c) 6.00 d) 5.1 x 105 e) 0.133
Science fiction often uses nautical analogies to describe space travel. If the starship U.S.S. Enterprise is traveling at warp factor 1.71, what is its speed in knots and in miles per hour'? (Warp 1.71 = 5.00 times the speed of light; speed of light = 3.00 x 108 m/s; 1 knot = 2030 yd/h.)