Hello sir Muttalibi is a step solution in detailing mathematics the s ame as an existing step solution EXAMPLE 6-1 Momentum-Flux Correction Factor for Laminar Pipe Flow Vavg Consider laminar flow through a very long straight section of round pipe. It is shown in Chap. 8 that the velocity profile through a cross-sectional area of the pipe is parabolic (Fig. 6-15), with the axial velocity component given by r4 V R V = 2Vavg (1) R2 where R is the radius of the inner wall of the pipe and Vag is the average velocity. Calculate the momentum-flux correction factor through a cross sec- tion of the pipe for the case in which the pipe flow represents an outlet of the control volume, as sketched in Fig. 6-15. Assumptions 1 The flow is incompressible and steady. 2 The control volume slices through the pipe normal to the pipe axis, as sketched in Fig. 6-15. Analysis We substitute the given velocity profile for V in Eq. 6-24 and inte- grate, noting that dA, = 2mr dr, FIGURE 6-15 4 dA, = TR2 Velocity profile over a cross section of a pipe in which the flow is fully developed and laminar. B = 1- 2nr dr (2) Defining a new integration variable y = 1- r2/R? and thus dy = -2r drlR2 (also, y = 1 atr 0, and y = 0 at r = R) and performing the integra- For turbulent flow ßmay have tion, the momentum-flux correction factor for fully developed laminar flow an insignificant effect at inlets becomes and outlets, but for laminar A = -4 [r dy = -- flow Bmay be important and (3) should not be neglected. It is wise to include Bin all Laminar flow: %3D Discussion We have calculated B for an outlet, but the same result would have been obtained if we had considered the cross section of the pipe as an inlet to the control volume. momentum control volume problems.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
icon
Related questions
Question
Hello sir Muttalibi is a step
solution in detailing
mathematics the same as an
existing step solution
EXAMPLE 6-1
Momentum-Flux Correction Factor
for Laminar Pipe Flow
CV
Vavg
Consider laminar flow through a very long straight section of round pipe. It
is shown in Chap. 8 that the velocity profile through a cross-sectional area of
the pipe is parabolic (Fig. 6-15), with the axial velocity component given by
r4
V
R
V = 2V
1
avg
R2
(1)
where R is the radius of the inner wall of the pipe and Vavg is the average
velocity. Calculate the momentum-flux correction factor through a cross sec-
tion of the pipe for the case in which the pipe flow represents an outlet of
the control volume, as sketched in Fig. 6-15.
Assumptions 1 The flow is incompressible and steady. 2 The control volume
slices through the pipe normal to the pipe axis, as sketched in Fig. 6-15.
Analysis We substitute the given velocity profile for V in Eq. 6-24 and inte-
grate, noting that dA, = 2ar dr,
FIGURE 6–15
%3D
Velocity profile over a cross section
of a pipe in which the flow is fully
developed and laminar.
V
4
2rr dr
R²
B =
(2)
V
avg
TR²
Defining a new integration variable y = 1 - r2/R? and thus dy = -2r dr/R2
(also, y = 1 at r = 0, and y = 0 at r = R) and performing the integra- For turbulent flow B may have
tion, the momentum-flux correction factor for fully developed laminar flow an insignificant effect at inlets
and outlets, but for laminar
flow Bmay be important and
(3) should not be neglected. It is
wise to include Bin all
becomes
10
4.
Laminar flow:
B = -4
y² dy
= -4
Discussion We have calculated B for an outlet, but the same result would
have been obtained if we had considered the cross section of the pipe as an
inlet to the control volume.
momentum control volume
problems.
Transcribed Image Text:Hello sir Muttalibi is a step solution in detailing mathematics the same as an existing step solution EXAMPLE 6-1 Momentum-Flux Correction Factor for Laminar Pipe Flow CV Vavg Consider laminar flow through a very long straight section of round pipe. It is shown in Chap. 8 that the velocity profile through a cross-sectional area of the pipe is parabolic (Fig. 6-15), with the axial velocity component given by r4 V R V = 2V 1 avg R2 (1) where R is the radius of the inner wall of the pipe and Vavg is the average velocity. Calculate the momentum-flux correction factor through a cross sec- tion of the pipe for the case in which the pipe flow represents an outlet of the control volume, as sketched in Fig. 6-15. Assumptions 1 The flow is incompressible and steady. 2 The control volume slices through the pipe normal to the pipe axis, as sketched in Fig. 6-15. Analysis We substitute the given velocity profile for V in Eq. 6-24 and inte- grate, noting that dA, = 2ar dr, FIGURE 6–15 %3D Velocity profile over a cross section of a pipe in which the flow is fully developed and laminar. V 4 2rr dr R² B = (2) V avg TR² Defining a new integration variable y = 1 - r2/R? and thus dy = -2r dr/R2 (also, y = 1 at r = 0, and y = 0 at r = R) and performing the integra- For turbulent flow B may have tion, the momentum-flux correction factor for fully developed laminar flow an insignificant effect at inlets and outlets, but for laminar flow Bmay be important and (3) should not be neglected. It is wise to include Bin all becomes 10 4. Laminar flow: B = -4 y² dy = -4 Discussion We have calculated B for an outlet, but the same result would have been obtained if we had considered the cross section of the pipe as an inlet to the control volume. momentum control volume problems.
Expert Solution
steps

Step by step

Solved in 3 steps with 3 images

Blurred answer
Knowledge Booster
Fluid Dynamics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Elements Of Electromagnetics
Elements Of Electromagnetics
Mechanical Engineering
ISBN:
9780190698614
Author:
Sadiku, Matthew N. O.
Publisher:
Oxford University Press
Mechanics of Materials (10th Edition)
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:
9780134319650
Author:
Russell C. Hibbeler
Publisher:
PEARSON
Thermodynamics: An Engineering Approach
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:
9781259822674
Author:
Yunus A. Cengel Dr., Michael A. Boles
Publisher:
McGraw-Hill Education
Control Systems Engineering
Control Systems Engineering
Mechanical Engineering
ISBN:
9781118170519
Author:
Norman S. Nise
Publisher:
WILEY
Mechanics of Materials (MindTap Course List)
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:
9781337093347
Author:
Barry J. Goodno, James M. Gere
Publisher:
Cengage Learning
Engineering Mechanics: Statics
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:
9781118807330
Author:
James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:
WILEY